Answer: physical change
Explanation: if you break glass it is still glass it did not change to another substance so it is just a physical change.
Answer:
All of the listed responses are correct.
Explanation:
Stimuli in the environment activate specialized receptor cells in the peripheral nervous system. Different types of stimuli are sensed by various types of receptor cells. Receptor cells can be classified into types on three different criteria:
1.cell type
2.position,
3. function.
Receptors can be classified structurally on the basis of cell type and their position in relation to stimuli they sense. classification can be functionally on the basis of the transduction of stimuli, or how the mechanical stimulus, photo, or chemical changed the cell membrane potential. An exteroceptor is a receptor that is located near a stimulus in the surrounding environment, example is the somatosensory receptors that can be found in the dermis
Answer:
Explanation:
P = 1.84 x 10³ N / 1.20² m² = 1,277.77777... N/m²
P = 1.28 x 10³ Pa
The motion of the tennis ball on the vertical axis is an uniformly accelerated motion, with deceleration of
![g=-9.81 m/s^2](https://tex.z-dn.net/?f=g%3D-9.81%20m%2Fs%5E2)
(gravitational acceleration).
The component of the velocity on the y-axis is given by the following law:
![v_y(t) = v_{y0}+gt](https://tex.z-dn.net/?f=v_y%28t%29%20%3D%20v_%7By0%7D%2Bgt)
At the time t=0.5 s, the ball reaches its maximum height, and when this happens, the vertical velocity is zero (because it is a parabolic motion):
![v_y(0.5 s)=0](https://tex.z-dn.net/?f=v_y%280.5%20s%29%3D0)
. Substituing into the previous equation, we find the initial value of the vertical component of the velocity:
![v_{y0}=-gt=-(-9.81 m/s^2)(0.5 s)=4.9 m/s](https://tex.z-dn.net/?f=v_%7By0%7D%3D-gt%3D-%28-9.81%20m%2Fs%5E2%29%280.5%20s%29%3D4.9%20m%2Fs)
However, this is not the final answer. In fact, the ball starts its trajectory with an angle of
![30^{\circ}](https://tex.z-dn.net/?f=30%5E%7B%5Ccirc%7D)
. This means that the vertical component of the initial velocity is
![v_{y0}=v_0 sin 30^{\circ}](https://tex.z-dn.net/?f=v_%7By0%7D%3Dv_0%20sin%2030%5E%7B%5Ccirc%7D)
We found before
![v_{0y}=4.9 m/s](https://tex.z-dn.net/?f=v_%7B0y%7D%3D4.9%20m%2Fs)
, so we can substitute to find
![v_0](https://tex.z-dn.net/?f=v_0)
, the initial speed of the ball:
To determine the distance of the light that has traveled given the time it takes to travel that distance, we need a relation that would relate time with distance. In any case, it would be the speed of the motion or specifically the speed of light that is travelling which is given as 3x10^8 meters per second. So, we simply multiply the time to the speed. Before doing so, we need to remember that the units should be homogeneous. We do as follows:
distance = 3x10^8 m/s ( 8.3 min ) ( 60 s / 1 min ) = 1.494x10^11 m
Since we are asked for the distance to be in kilometers, we convert
distance = 1.494x10^11 m ( 1 km / 1000 m) = 149400000 km