Answer:
The RTP (real time protocol) which uses the UDP ( user datagram protocol) and Real-time control protocol.
Explanation:
The RTP of a voice over IP protocol (VoIP) which is used to prioritise the transfer of video and audio data over text data. It is used for video conferencing and telephony services in an enterprise.
It uses the user-datagram protocol to transfer or access videos and audio data for its real time effect and the real-time control protocol for quality of service analysis and maintenance.
Answer:
Check the explanation
Explanation:
There are certainly many ways through which we can access and share database. The different ways to share an access database are as follows:
1. By using Sharepoint site: To utilize the SharePoint you should have windows SharePoint services server enabled on your system. Sharepoint assists in making database accessing very convenient by using methods like linking to list and publishing a database.
2. By using database server: This technique split a database that the tables are stored on the network in which each user has a copy of an access database file. The database file comprises of tables which contain queries, reports, forms, and other database objects.
3. By using split database: This technique is utilized when a database server product or a SharePoint site is unavailable. The tables then gains access into one access file and everything goes to other access files.
4. Network Folder: In this technique database file is stored on a shared network device and users can use the file simultaneously.
Below is the table for necessary hardware and software:
Sharepoint database split Network
site server database Folder
Need for database server software?No Yes No No
Need for windows server? Yes No No No
Answer:
def sum_1k(M):
s = 0
for k in range(1, M+1):
s = s + 1.0/k
return s
def test_sum_1k():
expected_value = 1.0+1.0/2+1.0/3
computed_value = sum_1k(3)
if expected_value == computed_value:
print("Test is successful")
else:
print("Test is NOT successful")
test_sum_1k()
Explanation:
It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.
- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.
- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message
- Call the <em>test_sum_1k()</em> to see the result
Int main(void){
int n,s=0;
while(1){
scanf(" %d",&n);
if(n<0) break;
s+=n;
}
printf("sum=%d\n",s);
return 0;
}
Answer:
public boolean equals(Object other)
{
// check correct instance
if (other instanceof IntTree)
{
try
{
IntTree otherTree = (IntTree) other;
return equals(overallRoot, otherTree.overallRoot);
}
// caught exceptions
catch (Exception e)
{
return false;
}
}
return false;
}
public boolean equals(IntTreeNode tree1, IntTreeNode tree2)
{
// if reach ends
if (tree1 == null && tree2 == null)
{
// they are equal
return true;
}
else if (tree1 == null || tree2 == null)
{
// not equal
return false;
}
// check left part
boolean leftPart = equals(tree1.left, tree2.left);
// check current element is same
boolean currentPart = tree1.element.equals(tree2.element);
// check right part
boolean rightPart = equals(tree1.right, tree2.right);
// all are equal
return (leftPart && currentPart && rightPart);
}
Explanation:
