Answer:
1 cookie = $1.25 1 cake = $15
Step-by-step explanation:
set up a system of equations:
let x = 1 cookie
let y = 1 cake
3x + 5y = 78.75
8x + 2y = 40
I multiplied the first equation by 2 to get: 6x + 10y = 157.50
I multiplied the second equation by -5 to get: -40x - 10y = -200.00
If you add both equations, the y-terms will be eliminated
-34x = -42.50
x = 1.25
Plug in 1.25 into equation to find value of y: 8(1.25) + 2y = 40
10 + 2y = 40
2y = 30
y = 15
Answer:
Q(-10) = 299
Step-by-step explanation:
![Q(x) = 3x^{2} - 1](https://tex.z-dn.net/?f=Q%28x%29%20%3D%203x%5E%7B2%7D%20-%201)
![Q(-10) = 3(-10)^{2} - 1](https://tex.z-dn.net/?f=Q%28-10%29%20%3D%203%28-10%29%5E%7B2%7D%20-%201)
(-10 to the second power is 100 (negative times a negative equals a positive)
3 times 100 equal 300
![Q(-10) = 299](https://tex.z-dn.net/?f=Q%28-10%29%20%3D%20299)
3 of each jessica can get 3 packs of cookies and 3 packs of cupcakes
Answer:
20y + 24.5
Step-by-step explanation:
10 (2y+2.45)
(10 * 2y) + (10 * 2.45)
20y + 24.5