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tino4ka555 [31]
3 years ago
15

Work out m and c for the line: 3 y + 6 x = − 3

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

<u>m</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u><u> </u><u>and</u><u> </u><u>c</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

Step-by-step explanation:

• Let's first phrase out the general equation of a line

{ \rm{y = mx + c}}

  • m is the slope
  • c is the y-intercept

[ remember that a general line equation must be in slope - intercept form as shown above ]

• from our question, we are given the equation;

{ \rm{3y + 6x =  - 3}}

• let's make y the subject in order to make the equation in slope - intercept format.

→ <em>r</em><em>e</em><em>m</em><em>e</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em>t</em><em>o</em><em> </em><em>a</em><em>p</em><em>p</em><em>l</em><em>y</em><em> </em><em>"</em><em>s</em><em>u</em><em>b</em><em>j</em><em>e</em><em>c</em><em>t</em><em> </em><em>m</em><em>a</em><em>k</em><em>i</em><em>n</em><em>g</em><em> </em><em>k</em><em>n</em><em>o</em><em>w</em><em>l</em><em>e</em><em>d</em><em>g</em><em>e</em><em>"</em>

{ \rm{3y =  - 3 - 6x}} \\  \\ { \rm{3y =  - 6x - 3}} \\  \\ { \rm{ \frac{3y}{3}  =  \frac{ - 6x}{3}  -  \frac{3}{3} }} \\  \\  { \boxed{ \rm{y =  - 2x - 1}}}

• The above boxed equation is now a general equation. Let's extract out slope, m and y-intercept, c

{ \rm{m \:  \dashrightarrow \:  - 2}} \\  \\ { \rm{c \:  \dashrightarrow \:  - 1}}

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