All categories

2 years ago

What is 1 + 1????????? ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Mathematics

1 answer:

jekas [21]2 years ago

6 0

Answer:

1+1=2

Step-by-step explanation:

If you have one cookie and add another cookie that's your second cookie.

You might be interested in

Billy anderson is choosing between two fitness centers. Center A charges $495 per year for unlimited use of all facilities. Cent

Darya [45]

Let's compare the cost of both the centers.

Cost of Center A:

One time charge of $495 in one year.

Cost of Center B:

Flat $25 dollar sign up fee
$15 per month, so $15*12=180$ dollars a year
$5 per aerobic class, so $5*52=260$ dollars a year (given that Billy goes to class once a week) (Note: There are 52 weeks in a year)

Total cost = $25+180+260=465$ dollars

Hence, Center B would cost $495-465=30$ dollars cheaper.

ANSWER: Least expensive club for Billy to use for a year is Center B

7 0

3 years ago

Read 2 more answers

Evaluate the difference quotient for the given function. Simplify your answer.

hammer [34]

Answer:

-2-h

Step-by-step explanation:

It doesn't hurt to follow directions.

$q=\dfrac{f(3+h)-f(3)}{h}=\dfrac{(5 +4(3+h)-(3+h)^2)-(5 +4(3)-(3)^2)}{h}\\\\=\dfrac{5-5+4(3+h-3)-((3+h)^2-3^2)}{h}=\dfrac{4h-(6h+h^2)}{h}\\\\=\dfrac{-2h-h^2}{h}=\boxed{-2-h}$

Steps: substitute 3+h and 3 for x in the definition of f(x) and simplify the result.

5 0

3 years ago

Find the degree of the polynomial b5 + 2b3 + 7.

scoray [572]

Answer:

Step-by-step explanation:

b^5 + 2b^3 + 7

Here,

degrees are 5 and 3.

The degree of the polynomial is the highest / greatest number in the degree.

Out of 3 and 5

5 is the highest / greatest number.

Hence,

the degree of the given polynomial is 5.

4 0

2 years ago

1/1×3 + 1/3×5 + ... + 1/47×49 HELP PLZ

Natalka [10]

Answer:

24/49

Step-by-step explanation:

Let's add the terms and see if there's a pattern

$\dfrac{1}{1\times 3}+\dfrac{1}{3\times 5}=\dfrac{5+1}{1\times 3\times 5}=\dfrac{2}{5}\quad\text{sum of 2 terms}\\\\\dfrac{2}{5}+\dfrac{1}{5\times 7}=\dfrac{14+1}{5\times7}=\dfrac{3}{7}\quad\text{sum of 3 terms}$

Suppose we say the sum of n terms is (n/(2n+1)), the next term in the series will be 1/((2n+1)(2n+3)) and adding that to the presumed sum gives ...

$\dfrac{n}{2n+1}+\dfrac{1}{(2n+1)(2n+3)}=\dfrac{n(2n+3)+1}{(2n+1)(2n+3)}=\dfrac{2n^2+3n+1}{(2n+1)(2n+3)}\\\\=\dfrac{(2n+1)(n+1)}{(2n+1)(2n+3)}=\dfrac{n+1}{2n+3}\text{ matches }\dfrac{(n+1)}{2(n+1)+1}$