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3 years ago

How do you explain how to get h(t)=7(t-25)

1 answer:

Nutka1998 [239]3 years ago

8 0

Hey There! :)

To Solve for t.
$h(t)=7(t-25)$
Distribute the brackets.
$h(t)=7*t-7*25$
$h(t)=7t-175$
Subtract 7t from both sides.
$(h(t))-7t=(7t-175)-7t$
$(h(t)-7t=-175$
$h*t-7t=-175$
Factor out variable, t.
$t(h-7)=-175$
Divide both sides by h-7.
$(t(h-7))/h-7=(-175)/h-7$
$t=-175/h-7$

Hope this helps!
-Benjamin

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A geometry class has a total of 27 students. The number of females is 13 less than the number of males. How many males and how m

boyakko [2]

Answer:

20 males and 7 females

Step-by-step explanation:

Let's say the number of females is x and the number of males is y.

We know that the total number of students is 27, which can also be written as x + y. So, these two expressions are equal: x + y = 27.

There are 13 fewer females than males, so: x = y - 13.

Now, we can use substitution to solve this system of linear equations.

Since x = y - 13, we can plug in y - 13 for x in x + y = 27:

x + y = 27 ⇒ (y - 13) + y = 27 ⇒ 2y - 13 = 27 ⇒ 2y = 40 ⇒ y = 20

Then, we use this value of y to solve for x:

x = y - 13 = 20 - 13 = 7

Thus, there are 20 males and 7 females.

Hope this helps!

6 0

3 years ago

Read 2 more answers

X2+6/5x+8/25 please help me.

Dmitriy789 [7]

The answer to your question is:

x^2 + 6/5x + 8/25;

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3 years ago

What is the distance between the points (13,20) and (18,8)

Eva8 [605]

√((18-13)^2+(20-8)^2)= 13

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3 years ago

Let u = <-9,4>, v = <8, -5>. Find u - v.

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or in polar form

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3 years ago

If the vertex of a parabola is (3,5), what is the symmetry

alisha [4.7K]

Answer:

axis of symmtery: x = 3 or h = 3

Step-by-step explanation:

The vertex (h, k) of a parabola is the point wherein the graph intersects the axis of symmetry—the imaginary straight line that bisects a parabola into two symmetrical parts, where x = h.

In the standard form of quadratic equation, y = ax² + bx + c, the equation of the axis of symmetry is: $x = \frac{-b}{2a}$ .

In the vertex form of the quadratic equation, y = a(x - h)² + k, the equation of the axis of symmetry is: $h = \frac{-b}{2a}$ .

Regardless of whether the quadratic equation is in standard or vertex form, the x-coordinate (h) of the vertex determines the axis of symmtetry, hence, x = h. 

Therefore, given that the vertex of a parabola is at point (3, 5), then it means that the axis of symmetry occurs at x = 3 or h = 3.

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2 years ago