Answer:
You have to make a frequency table.
Step-by-step explanation:
The classes are
.320- .329
.330-.339
.340 - .349
.350 - .359
.360 - .369
Then, you have to find to find how many values would fall into the class of .340 - .349.
<h2>Classes are basically compound inequalities. </h2>
.320 ≤ x ≤.329
All x values that are less than (or equal to) .329 but greater than .320 fall into the class of
.320- .329.
Frequency is just how many numbers are in a class.
Pretty sure the answer is C - if not that then A
The percentage of increase in area will be 300%
<em><u>Explanation</u></em>
By doubling each dimension, the area of a parallelogram increased from 36 square centimeters to 144 square centimeters.
So, the increased area = Final area - Initial area = (144 - 36)cm² = 108 cm²
Now, for finding the percentage of increase, first we need to <u>divide "the increased area" by the "initial area" and then multiply by 100% </u>
Thus, the percentage of increase in area %
Answer:
Step-by-step explanation:
- 8x + 44 ≥ 60
Subtract 44 from both sides
- 8x + 44 - 44 ≥ 60 - 44
- 8x ≥ 16
Divide both sides by -8 and flip the inequality sign
-8x/-8 ≤ 16/-8
x ≤ -2
x = { ......... -4,-3,-2}
2) -4x + 50 < 58
Subtract 50from both sides
-4x + 50 -50 < 58- 50
-4x < 8
Divide both sides by -4 and flip the inequality sign
-4x/-4 > 8/-4
x > -2
x= {-1, 0 , 1 , 2....... }