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Advocard [28]
3 years ago
12

A parallelogram is shown below: Part A: What is the area of the parallelogram? Show your work. (5 points) Part B: How can you de

compose this parallelogram into two triangles? If this parallelogram was decomposed into two triangles, what would be the area of each triangle?

Mathematics
2 answers:
kirill115 [55]3 years ago
8 0

Answer:

<u><em>Part A) Area of Parallelogram:</em></u>

Area = Base*Height

Area = 3 * \frac{2}{3}

<u><em>Area = 2 feet²</em></u>

<u><em>Part B)</em></u>

We can  decompose the parallelogram into two triangle by drawing a diagonal which will divide the parallelogram into two triangles with equal area

<u><em>Part C)</em></u>

The area of each triangle would be the half of the area of parallelogram.

=> <u><em>Area of each triangle = 2 feet²/2 = 1 feet ²</em></u>

aksik [14]3 years ago
5 0

Part A) The area of a parallelogram is base × height.

3 × 2/3 = 6/3 = 2

2 feet squared is the area of the whole parallelogram.

Part B) The diagonal of a parallelogram separates it into two congruent triangles.

The area of each triangle will be:

base × height × 1/2

3 × 2/3 × 1/2 = 6/6 = 1

1 foot squared is the area for each triangle.

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sladkih [1.3K]

Answer:

The answer is shown below

Step-by-step explanation:

Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.

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b)

\frac{dy}{dt}=ky(1-y)\\\frac{dy}{y(1-y)}=kdt\\\int\limits {\frac{dy}{y(1-y)}} \, =\int\limit {kdt}\\\int\limits {\frac{dy}{y}} +\int\limits {\frac{dy}{1-y}}  =\int\limit {kdt}\\\\ln(y)-ln(1-y)=kt+c\\ln(\frac{y}{1-y}) =kt+c\\taking \ exponential \ of\ both \ sides\\\frac{y}{1-y} =e^{kt+c}\\\frac{y}{1-y} =e^{kt}e^c\\let\ A=e^c\\\frac{y}{1-y} =Ae^{kt}\\y=(1-y)Ae^{kt}\\y=\frac{Ae^{kt}}{1+Ae^{kt}} \\at \ t=0,y=10\%\\0.1=\frac{Ae^{k*0}}{1+Ae^{k*0}} \\0.1=\frac{A}{1+A} \\A=\frac{1}{9} \\

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Answer:
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3 years ago
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The length of time to complete a door assembly on an automobile factory assembly line is normally distributed with a mean of 6.7
hram777 [196]
We need to work out the z-value of each question to work out the probability

Question a)

We have
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