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lions [1.4K]
3 years ago
9

Combine these things :/ 5 Times Sqrt 27 - 17 Times Sqrt 3 Please explain and thank you :P

Mathematics
1 answer:
bearhunter [10]3 years ago
5 0

Answer:

-2 \sqrt{3}

Step-by-step explanation:

Given

5 * \sqrt{27} - 17 * \sqrt{3}

Required

Combine both

5 * \sqrt{27} - 17 * \sqrt{3}

Express 27 as 9 * 3

5 * \sqrt{9 * 3} - 17 * \sqrt{3}

Split:

5 * \sqrt{9} * \sqrt{3} - 17 * \sqrt{3}

5 * 3 * \sqrt{3} - 17 * \sqrt{3}

15 * \sqrt{3} - 17 * \sqrt{3}

15  \sqrt{3} - 17 \sqrt{3}

-2 \sqrt{3}

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A probability experiment is conducted in which the sample space of the experiment is Sequals=StartSet 9 comma 10 comma 11 comma
White raven [17]

Answer:

From both approaches P(F or G)=0.667

Step-by-step explanation:

P(F or G)=?

F={9, 10, 11, 12, 13}​

G={13,14,15,16}

Finding P(F or G) by counting outcomes in F or G

F or G={9, 10, 11, 12, 13}or {13,14,15,16}

F or G={9, 10, 11, 12,13,14,15,16}

number of outcomes in F or G=n(F or G)=8

S={9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}​

number of outcomes in S=n(S)=12

P(F or G)=n(F or G)/n(S)

P(F or G)=8/12

P(F or G)=0.667

Finding P(F or G) by addition rule

P(F or G)=P(F)+P(G)-P(F and G)

F={9, 10, 11, 12, 13}​

number of outcomes in F=n(F)=5

P(F)=n(F)/n(S)

P(F)=5/12

P(F)=0.417

G={13,14,15,16}

number of outcomes in G=n(G)=4

P(G)=n(G)/n(S)

P(G)=4/12

P(G)=0.333

F and G={9, 10, 11, 12, 13}and {13,14,15,16}

F and G={13}

number of outcomes in F and G=n(F and G)=1

P(F and G)=n(F and G)/n(S)

P(F and G)=1/12

P(F and G)=0.083

P(F or G)=P(F)+P(G)-P(F and G)

P(F or G)=0.417+0.333-0.083

P(F or G)=0.667

8 0
2 years ago
Read 2 more answers
SOMEONE NEEDS TO EXPLAIN WHY 1.40 DIDNT WORK ON MY QUESTION 2.1/1.488
Zanzabum

My calculator shows that

(2.1)/(1.488) = 1.41129

which is approximate. If you want the result to two decimal places, then it would be 1.41 and not 1.40

Try 1.41 and it should work out, assuming your teacher wants two decimal places.

7 0
2 years ago
Multiply.
Evgesh-ka [11]
The answer is -2.76.

Hope I Helped                                   (=^-^=)
8 0
3 years ago
Read 2 more answers
Please help I would reall6 appreciate it
madreJ [45]
Help with what? Have a question or a picture to show?
3 0
2 years ago
A corporation has 11 manufacturing plants. Of these, seven are domestic and four are outside the United States. Each year a perf
nikdorinn [45]

Answer:

The probability that a performance evaluation will include at least one plant outside the United States is 0.836.

Step-by-step explanation:

Total plants = 11

Domestic plants = 7

Outside the US plants = 4

Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:

P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ

where n = total no. of trials

           x = no. of successful trials

           p = probability of success

           q = probability of failure

Here we have n=4, p=4/11 and q=7/11

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰

          = 1 - 0.16399

P(X≥1) = 0.836

The probability that a performance evaluation will include at least one plant outside the United States is 0.836.

7 0
2 years ago
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