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lorasvet [3.4K]

2 years ago

7

A chocolate factory makes 6060 chocolates in an hour .How many chocolates can it make in a day , if the factory is operational f

or 13 hours?
I want in step by step please ....

1 answer:

dimulka [17.4K]2 years ago

6 0

Answer:

78,780

Step-by-step explanation:

Given:

6060 chocolates made per hour
13 hours in one day

Number of chocolates made in 1 day = number of chocs/hr × number of hours

= 6060 × 13

= 78,780

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The graph below represents the amount of change Jaxon would receive, y, if he bought a item with a cost of x.

alexira [117]

Answer:

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Step-by-step explanation:

I don't know the answer

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3 years ago

Which fraction is equivalent to 5(z+3)-4(1+p)?<br><br> A. 15z-4p<br> B. 5z+19+4p<br> C. 5z+11-4p

Mila [183]

C 5z+11-4p.

5(z+3)-4(1+p)
5z+15-4-4p
5z+11-4p

8 0

2 years ago

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

<u>For urn 2</u>

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

2 years ago

Every evening Jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she

Sergeeva-Olga [200]

A) .10 d + .25 q = 7.75
B) d + q = 40

Multiplying B) by -.10
B) -.10d -.10q = -4.0
Then adding this to A)
A) .10 d + .25 q = 7.75
.15q = 3.75

Quarters = 25
Therefore, dimes = 15
***************************************************
Double-Check
A) .10 d + .25 q = 7.75
A) .10 * 15 d + .25 * 25 = 7.75
A) 1.50 + 6.25 = 7.75

Correct!!

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2 years ago

Two groups of workers are painting a bridge in the bay. The first group is responsible for painting the north side of the bridge

artcher [175]

Answer:

They will each have painted 8 km. This goal will be met on Day 4.

Step-by-step explanation:

Group A | Group B

Start: 2 | Start: 5 Day 1

2 + 2 = 4 | 5 + 1 = 6 Day 2

4 + 2 = 6 | 6 + 1 = 7 Day 3

6 + 2 = 8 | 7 + 1 = 8 Day 4

4 0

3 years ago