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3 years ago

I need help to do this task I do not understand!☹️

Mathematics

1 answer:

Misha Larkins [42]3 years ago

4 0

To rotate a point 180 degrees, you simply multiply both the x and y value by -1. For example, for A (-7, 1) we can rotate it 180 degrees to get (-7*-1, 1*-1)=(7, -1)

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2 pizzas para 3 personas cuanto les toca a cada uno

Masja [62]

5.3 pedasos de pizza

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3 years ago

A closed cylindrical vessel contains a fluid at a 5MPa pressure. The cylinder, which has an outside diameter of 2500mm and a wal

Julli [10]

Answer:

1) Increase in the diameter equals 3.5 mm

2) Increase in the length equals $0.0003724L_{i}$ where $L_{i}$ is the initial length of the vessel.

Step-by-step explanation:

The diametric strain in the vessel is given by

$\epsilon_{D} =\epsilon_{diam}-\nu \epsilon _{axial}$

We have

$\epsilon _{diam}=\frac{\sigma _{hoop}}{E}\\\\\sigma _{hoop}=\frac{\Delta P\times D}{2t}\\\\\therefore \epsilon _{diam}=\frac{\Delta P\times D}{2t\times E}$

Applying values we get

$\therefore \epsilon _{diam}=\frac{5\times 10^{6}\times 2.5}{2\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{5}{3088}$

Similarly axial strain is given by

$\epsilon _{diam}=\frac{\sigma _{axial}}{E}$

$\sigma _{axial}=\frac{\Delta P\times D}{4t}\\\\\therefore \epsilon _{axial}=\frac{\Delta P\times D}{4t\times E}$

Applying values we get

$\therefore \epsilon _{axial}=\frac{5\times 10^{6}\times 2.5}{4\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{2.5}{3088}$

Hence The effect of axial strain along the diameter is given by

$-\nu \epsilon _{axial}$

Applying values we get

$-\nu \epsilon _{axial}=-0.27\times \frac{2.5}{3088}=-0.0002185$

hence

$\epsilon _{D} =\frac{5}{3088}-0.0002185\\\\\epsilon =0.00140$

Now by definition of strain we have

$\epsilon _{D} =\frac{D_{f}-D_{i}}{D_{i}}\\\\\therefore D_{f}=D_{i}+\epsilon D_{i}\\\\D_{f}=2.5+0.0014\times 2.5\\\\\therefore D_{f}=2503.5mm$

Increase in the diameter is thus 3.5 mm

Using the same procedure for axial strain we have

$\epsilon_{axial} =\epsilon_{axial}-\nu \epsilon _{diam}$

Applying values we get

$\epsilon_{axial} =\frac{2.5}{3088}-0.27\times \frac{5}{3088}$

$\epsilon_{axial} =0.0003724$

Now by definition of strain we have

$\epsilon _{axial} =\frac{L_{f}-L_{i}}{L_{i}}\\\\\therefore \Delta L=0.0003724L_{i}$

where $L_{i}$ is the initial length of the cylinder.

6 0

4 years ago

Write an equation of the line below

Ratling [72]

Answer:

y = 3/5 + 4

Step-by-step explanation:

Given Coordiantes:

(0,4) - Y-intercept

(5,7) - Coordinates

To make an equation, first find the slope.

$m=\frac{rise}{run} =\frac{y}{x}$

$m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

$m=\frac{7-4}{5-0}$

$m=\frac{3}{5}$

In decimals:

$m = 0.6$

Now convert to point slope.

$y-y_{1} =m(x-x_{1} )$

$y-4=\frac{3}{5} (x-0)$

In decimals:

$y-4=0.6(x-0)$

Now convert to slope-intercept form.

Find the Equation of the Line:

$y=mx+b$

by solving for y using the Point Slope Equation.

y = 3/5 + 4

8 0

3 years ago

Which steps should be used to graph the equation below? y-4=1/3(x+2)

juin [17]

-> First, we want to put it into more of a slope-intercept form so we can graph.

y - 4 = 1/3 (x + 2)

y = 1/3 (x + 2) + 4

y = 1/3x + 2/3 + 4

y = 1/3x + 14/3

-> Next, we will plot the point (0, 14/3) because it is the y-intercept of our equation

-> Last, we will move up one and to the right three, following the pattern of "rise over run" with our slope of 1/3

[] The finished graph is attached

[] I have also graphed the original equation to show that they overlap, showing that our simplification works

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

3 0

2 years ago

Work out m and c for the line:<br>y = 2x - 3

saveliy_v [14]

Answer:

m = 2

c = -3

Explanation:

Equation of Line ⇒ y = mx +c

y = 2x - 3

m = 2

c = -3

3 0

3 years ago

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