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gizmo_the_mogwai [7]
2 years ago
13

Please asapfor 10 points!​

Mathematics
1 answer:
kari74 [83]2 years ago
8 0
<h3>Given:</h3><h3>Large cone:</h3>
  • r= 8 cm
  • h= 20 cm
<h3>Small cone:</h3>
  • r= 4 cm
  • h= 10cm
<h3>Note that:</h3>
  • r: radius
  • h: height
<h3>To find:</h3>
  • The volume of the frustum of the given cone.
<h3>Solution:</h3>
  • Frustum is a part of a cone formed by cutting off the top by a parallel plane.

\large\boxed{Formula: V= \frac{1}{3}\pi{r}^{2}h}

Let's solve!

First, let's find the volume of the smaller cone.

Substitute the values according to the

formula.

V= \frac{1}{3}×\pi×{4}^{2}×10

V= 167.5516082 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in the thousandths place is smaller than 5 so we won't have to round up.

\boxed{V= 167.55 \: {cm}^{3}}

Next, let's find the volume of the bigger cone.

Substitute the values according to the formula.

V= \frac{1}{3}×\pi×{8}^{2}×20

V= 1340.412866 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in thousandths place is smaller than 5 so we won't have to round up.

\boxed{V=1340.41 \: {cm}^{3}}

Now, we can find the volume of the frustum.

We'll have to minus the volume of the smaller cone from the bigger cone.

V= 1340.41-167.55

\large\boxed{V= 1172.86 \: {cm}^{3}}

<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>



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yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2}  = \frac{1 \pm 9 }{-0.4}

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0
3 years ago
Consider the factor pairs of 100. When do the factor pair reverse Order?
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I need help with my puzzle I can't figure it out j
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3241004551 [841]

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Which expression is equivalent to 6–3?
Bond [772]

Your question is not well presented. See complete question below

Which expression is equivalent to 6^{-3}?

A) –63

B) 36

C) \sqrt[3]{6}

D) (\frac{1}{6} )^3

Answer:

The equivalent of 6^{-3 is (\frac{1}{6} )^3

Step-by-step explanation:

Given

Expression: 6^{-3}

Required:

Find the Equivalent Expression

To find the equivalent of this expression, we make use of law of indices.

One of the laws of indices states that

a^-b = \frac{1}{a^b}

If we apply this law to the expression above (6^{-3})

By comparison a = 6 and b = 3.

So, 6^{-3} becomes

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Simplifying further;

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This can also be written as

\frac{1}{6^3} = \frac{1*1*1}{6 * 6 * 6}

By splitting the above expression; we have that

\frac{1}{6^3} = \frac{1}{6} * \frac{1}{6} * \frac{1}{6}

Multiplication law of indices states that;

a * a * a = a³. (Because they have the same base of a)

So, \frac{1}{6} * \frac{1}{6} * \frac{1}{6} can then be written as (\frac{1}{6} )^3

Hence,  \frac{1}{6^3} = (\frac{1}{6} )^3

So, the equivalent of 6^{-3} is (\frac{1}{6} )^3

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given that sin x &lt; cos x and 0° &lt; x &lt; 90°, state a possible value of x. explain your answer clearly.​
Ahat [919]

Answer:

See below.

Step-by-step explanation:

When x has a value between 0 and 90 the values of sin x ranges from 0, if x = 0 and 1 , if x = 90 degrees.

The cosine of x  has the reverse  value: cos x is 1 for x = 0 and 0 for x = 90 degrees.

At x = 45 the sine and cosine are equal in value.

So for sin x < cos x the value of x must be between 0 and 45  degrees.

So a possible value of x  is 30 degrees.

When x = 30 sin x = 0.5 and cos x = 0.866.

7 0
3 years ago
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