Albert Einstein was a famous physicist.

The density of a hippo is approximately 1030kg/m^3,so it sinks to the bottom of the freshwater lakes and rivers. A 1500kg hippo

hram777 [196]

Answer:

14,700 N

Explanation:

The hyppo is standing completely submerged on the bottom of the lake. Since it is still, it means that the net force acting on it is zero: so, the weight of the hyppo (W), pushing downward, is balanced by the upward normal force, N:

$W-N=0$ (1)

the weight of the hyppo is

$W=mg=(1500 kg)(9.8 m/s^2)=14,700 N$

where m is the hyppo's mass and g is the gravitational acceleration; therefore, solving eq.(1) for N, we find

$N=W=14,700 N$

8 0

3 years ago

I need help with number 6 and 7 please and I’ll mark brainliest

arsen [322]

Answer:

n.6 is T

Explanation:

because mass always stays the same where ever you are but weight changes depending on the gravity

3 0

3 years ago

Read 2 more answers

A person travelled in the -x direction at a constant speed of 2.5 m/s. The person's final position is -10.0 m, and the initial p

Nostrana [21]

Answer:

(c) time required to travel = 8 sec

Explanation:

We have given the final position = -10 m on x axis

And the initial position =10 m

So total distance = 10-(-10)=20 m

The speed is given as 2.5 m/sec

We have tof ind the time required by the person to travel

Time is given by $t=\frac{distance}{speed}=\frac{20}{2.5}=8 sec$

So the option (c) is correct option

4 0

3 years ago

17. A distance-time graph indicates that an object moves 120 meters in 5 seconds and then remains at rest for 5 seconds. What is

irina1246 [14]

Answer:

12 m/s

Explanation:

Speed is distance moved per unit time and expressed as

S=d/t

S is speed, d is distance and t is time.

When at rest for five minutes, distance moved is zero hence speed is 0/5=0 m/s

When having moved 120 m for 5 s then speed is

S=120/5=24 m/s

Average speed is the average of these two speeda

Average speed=(24+0)÷2=24/2=12 m/s

Therefore, average speed is 12 m/s

3 0

2 years ago

An airplane is heading due south at a speed of 560 km/h . If a wind begins blowing from the southwest at a speed of 80.0 km/h (a

polet [3.4K]

Answer:

the magnitude of Vpg = 493.711 km/h

Explanation:

given data

speed Vpg = 560 km/h

speed Vwg = 80 km/h

solution

we get here magnitude of the plane velocity w.r.t. ground is

we know that the Vpg = Vpw + Vwg .....................1

writing the component of the velocity that is

Vpw = (0 km/h î - 560 km/h j )

Vwg = (80 cos 45 km/h î + 80 sin 45 km/h j)

adding these

Vpg = (0+80 cos 45 km/h ) î + ( -560 + 80 sin 45 km/h j)i

Vpg = (42.025 ) î (-491.92 km/h)j

now we take magnitude

the magnitude of Vpg = $\sqrt{(42.025^2+(-491.92)^2)} km/h$

the magnitude of Vpg = 493.711 km/h

5 0

2 years ago