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Alinara [238K]
3 years ago
7

Tom and Mary are riding a merry-go-round. Tom is on a horse about half way between the center and the outer rim, and Mary is on

a horse at the outer rim.
a) Which child has the larger angular speed? Explain



b) Which child has the larger linear speed? Explain



c) Which child has the larger radial acceleration? Explain
Physics
1 answer:
iren2701 [21]3 years ago
7 0

Answer:

Explanation:

Given

Tom is on half way between the center and the outer rim

Mary is on the extreme outer rim

Suppose \omega is the angular velocity of ride with radius of outer rim be R

\alpha =angular acceleration of Ride

At any instant both Tom and Mary experience the same angular speed

(b)Linear velocity at any instant

v_{Tom}=\omega \times R

v_{Mary}=\omeag \times \frac{R}{2}

Thus Tom has higher linear speed

(c) For radial Acceleration

a_r=\omega ^2\times r

a_{Tom}=\omega ^2\times R

a_{Mary}=\omega ^2\times \frac{R}{2}

Tom has higher radial Acceleration as it is directly Proportional of radius          

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In a carnival booth, you can win a stuffed giraffe if you toss a quarter into a small dish. the dish is on a shelf above the poi
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components of the speed of the coin is given as

v_x = v cos60

v_x = 6.4 cos60 = 3.2 m/s

v_y = vsin60

v_y = 6.4 sin60 = 5.54 m/s

now the time taken by the coin to reach the plate is given by

t = \frac{\delta x}{v_x}

t = \frac{2.1}{3.2}

t = 0.656 s

now in order to find the height

h = vy * t + \frac{1}{2} at^2

h = 5.54 * 0.656 - \frac{1}{2}*9.8*(0.656)^2

h = 1.52 m

so it is placed at 1.52 m height

3 0
3 years ago
1. An excited lithium atom emits a red light with wavelength a = 671nm. What is the corresponding photon energy? hc (6.63 x 10-3
Rudiy27

Answer:

 E = 2,964 10⁻¹⁹ J

Explanation:

The energy of the photons is given by the Planck relation

          E = h f

the speed of light is related to wavelength and frequency

          c = λ f

we substitute

          E = h c /λ

let's reduce the magnitude to the SI system

          λ = 671 nm = 671 10⁻⁹ m

let's calculate

          E = 6.63 10⁻³⁴ 3 10⁸ /671 10⁻⁹

          E = 2,964 10⁻¹⁹ J

6 0
3 years ago
A railroad car is pulled through the distance of 960 m by a train that did 578 kJ of work during this pull.
Wittaler [7]

Answer:

<h2>602.08 N</h2>

Explanation:

The force supplied by the train can be found by using the formula

f =   \frac{w}{d}  \\

w is the workdone

d is the distance

From the question we have

f =  \frac{578000}{960}  \\  = 602.083333...

We have the final answer as

<h3>602.08 N</h3>

Hope this helps you

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3 years ago
What is a Geographic test
Genrish500 [490]
<em>It's a test on Geography!
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3 years ago
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For a bronze alloy, the stress at which plastic deformation begins is 294 MPa and the modulus of elasticity is 121 GPa. (a) What
FromTheMoon [43]

Answer:

a) load in Newton is 96,138 b) 129.314mm

Explanation:

Stress = force/ area (cross sectional area of the bronze)

Force(load) = 294*10^6*327*10^-6 = 96138N

b) modulus e = stress/ strain

Strain = stress/ e = (294*10^6)/ (121*10^ 9) = 2.34* 10^ -3

Strain = change in length/ original length = DL/ 129

Change in length DL = 129 * 2.34*10^ -3 = 0.31347

Maximum length = change in length + original length = 129.314mm

7 0
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