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Illusion [34]
3 years ago
10

An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir

cuit that "clicks" in response to current. The faster the current, the more clicks per minute. In this experiment, the number of clicks in one minute is recorded for each color of light shining on the photocell. To change the color of light, a different color of cellophane is placed over the same flashlight and the flashlight is then located a specific distance from the photocell.
Which of the following was not kept constant?


the color of the light after it has passed through the cellophane
the source of the original light
the distance of the light from the photocell
the test for photocell activation
Physics
1 answer:
Mariana [72]3 years ago
6 0

Answer:

the color of the light after it has passed through the cellophane

Explanation:

Since in the given experiment, there is an impact of various colors of light on the cell i.e. photoelectric that should be measured. The photocell should be placed in a circuit when the current would passed. For every color that falls on the photocell, the value of the current that passed via the cell represent an idea.

In the given situation the color of light shows an independent variable and the dependent variable is clicks per minute or the current that passed through the cell

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Answer:

5.959 m/s

Explanation:

m = Mass of gymnast

u = Initial velocity

v = Final velocity

h_i = Initial height

h_f = Final height

From conservation of Energy

\frac{1}{2}mv^2+mgh_f=\frac{1}{2}mu^2+mgh_i\\\Rightarrow\frac{1}{2}mv^2+mg0=\frac{1}{2}m0^2+mgh_i\\\Rightarrow \frac{1}{2}mv^2=mgh_i\\\Rightarrow v=\sqrt{2gh_i}

h_i=2r

v=\sqrt{4gr}\\\Rightarrow v=\sqrt{4\times 9.81\times 0.905}\\\Rightarrow v=5.959\ m/s

Velocity of gymnast at bottom of swing is 5.959 m/s

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4 years ago
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4 0
3 years ago
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Where are the magnetic<br> fields<br> strongest near a bar magnet?
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<h2>ANSWER:</h2>
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A signal is sampled at 10000 Hz and a total of 1024 data samples are taken, what are the highest and lowest frequencies that can
tia_tia [17]

Since the discrete Fourier series, the Sampling rate, would be the equivalent of the inverse of the passage of time, that is, to the frequency, mathematically this can be written as,

\frac{1}{\Delta t} = 10000Hz

In turn, the time can be described depending on the period and the amount of data samples taken. This would be,

\Delta t = \frac{T}{m}

Here,

m = Data Samples

T = Period

Replacing,

\Delta t = \frac{T}{1024}

Replacing the value of the time from the first equation,

\frac{1024}{T} = 10000

T = 102.4ms

At the same time, the range then will be given between the basic frequency to the half of the sample, that is,

f_{min} = \frac{1}{T} = 9.165Hz

f_{max} = \frac{1024}{2} (9.165Hz)

f_{max} = 5000Hz

Therefore the lowest frequency is 5000Hz and highest 9.165Hz

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3 years ago
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