Answer:
(i) 15 m, 6 m/s
(ii) 90 m
Step-by-step explanation:
(i) For some acceleration (a) from rest, the distance covered (d) in time t is ...
d = (1/2)at^2
The distance covered by Ben in the 5 seconds he is accelerating is ...
d = (1/2)(1.2 m/s²)(5 s)² = 15 m
Of course, Ben's speed at that point is ...
s = (1.2 m/s²)(5 s) = 6 m/s
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(ii) When Ben has been walking 5 s, Alan has been walking 10 s, so Alan has covered (10 s)(4 m/s) = 40 m. Their distance difference of 40 -15 = 25 m is being made up at the rate of their speed differences: (6 m/s) -(4 m/s) = 2 m/s.
It will take (25 m)/(2 m/s) = 12.5 s additional time for Ben to catch Alan. In the 22.5 s that Alan has been walking before they meet, he will have walked ...
(22.5 s)(4 m/s) = 90 m . . . the distance OP
15 pounds / 35 sandwiches ~ 0.43 pounds ham per sandwich
Answer:
36π
Step-by-step explanation:
d= 6 in
r= d/2=6/2= 3 in
volume of sphere= 4/3πr^3
=4/3 ×π×3^3
=36π in^3
Let's find what 1/6 of an hour is.
1/6×60=10
So, ten minutes is equal to 1/6 of an hour. Let's find hour many sets of 10 minutes are in six hours. Let's first find the amount of minutes.
6×60=360
360÷10
36
Let's multiply that by 94.
94×36
3,384 miles in 6 hours.
Angle K = angle M
(4x-1)=(2x+27)
4x-2x=27+1
2x=28
x=14
K=4x-1 then 4(14)-1
55 degrees
M=2x+27 then 2(14) +27
55 degrees
K+M+L =180
55+55+L=180
110+L=180
L=70 degrees
Therefore K=55 degrees M=55 degrees L=70 degrees