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emmainna [20.7K]
2 years ago
14

The diameter of a circle Is 8 inches . What is the area ?

Mathematics
2 answers:
Elena L [17]2 years ago
8 0

Answer:

radius=d/2 = 8/2 = 4inch.

Step-by-step explanation:

area = πr²

16π(inch)². or 352/7 (inch)².

hope this helps you.

luda_lava [24]2 years ago
4 0

Hello There!

GraceRosalia is here to help you!

We are given that

d=8 in.

We know that the radius is 1/2 of d or r=d/2. So the radius is 4.

However, we have to find the area.

The formula for the area of a circle is:

A=\pir^{2}

We know that r=4, so all we have to do is plug it into the formula:

A=\pi (4)^{2}

Remember that only the radius is squared.

A=\pi *16

A=50.265

Let's round to the nearest tenth:

A=50.3

Hope this helps you!

GraceRosalia

Let me know if you have any questions!

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The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

H_1: \mu_1 - \mu_2 \neq 0

We have a two-tailed test, as we are testing if the mean is different of a value.

Considering the significance level of 0.05, with 75 + 46 - 2 = 119 df, the critical value for the test is given as follows:

|t| = 1.9801.

Hence the decision rule is:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

More can be learned about the t-distribution in the test of an hypothesis at brainly.com/question/13873630

#SPJ1

3 0
1 year ago
What is the value of the 4 in 432?
amm1812
The value of 4 is Hundreds.
Your welcome
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3 years ago
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Which of the functions below could have created this graph?
bearhunter [10]

Answer:

A

Step-by-step explanation:

Two facts need to guide your answer.

One

The highest power is odd: you know this because an even power would start on the left come down do it's squiggles if had any and wind up on the right going up.

This graph comes down on the left does it's squiggles and then goes further down on the right. That's the behavior of something whose highest power is odd.

Two

The leading coefficient,  the number in front of the highest power must be minus. If it was positive as in y = x^3 the graph would be the mirror image of what it is.

Argument

B and D cannot be true. The highest power is even.

C is false because the leading coefficient is + 1.

So that leave A which is the answer.

The graph is included with this answer

7 0
3 years ago
How do I solve this equation?
Norma-Jean [14]

Answer:

1. move the constant to the right hand side to change its sign.

2.add the numbers.

3. using the absolute value definition rewrite the absolute value equation as two separate equations.

4.slove the equation for X

Step-by-step explanation:

it has two solutions

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Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7
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x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6

Let z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}. The ODE becomes

-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6
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\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4
x^6z=-6\displaystyle\int x^4\,\mathrm dx
x^6z=-\dfrac65x^5+C
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y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}
y=\dfrac1{\frac C{x^6}-\frac6{5x}}
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With y(3)=6, we get

6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2

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y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}

which is valid as long as the denominator is not zero, which is the case for all x\neq\sqrt[5]{\dfrac{4131}{12}}.
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