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Debora [2.8K]
3 years ago
15

I’m being timed, correct answer get brainliest

Mathematics
2 answers:
Lerok [7]3 years ago
8 0

Answer:

A, C, E

Step-by-step explanation:

If you choose A 0, you end up with a binomial, so A works.

If you choose B 5xy^3, it cancels out the existing -5xy^3 and you end up with only 1 term, so B does not work.

If you choose C 9x^2y, it adds to the 9x^2y and you have two terms. C works.

If you choose D 8y^4, you end up with 3 terms. D does not work.

If you choose E 4xy^3, it combines with -5xy^3, and you end up with two terms. E works.

Answer: A, C, E

malfutka [58]3 years ago
6 0
The answers would be A B and D i’m pretty sure
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Fantom [35]
I can’t see good this image
3 0
3 years ago
Evaluate the permutation P(36,19)=____
kondaur [170]
Easy

nPr=\frac{n!}{(n-r)!}
here
36P19=\frac{36!}{(36-19)!}=
\frac{36!}{(17)!}=
\frac{36*35*34*33*32*31*30*29*28*27*26*25*24*23*22*21*20*19*18}{1}=
1045843337171591729971200000





6 0
3 years ago
Kevin uses each of the digits 6, 4, 3 and 8, once and once only, to make four-digit numbers.
Lena [83]

Answer:

4683

Step-by-step explanation:

7 0
2 years ago
How are the rules for multiplying and dividing integers similar and how are they different?
3241004551 [841]

Answer:

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Step-by-step explanation:

5 0
3 years ago
My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and
Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1600, \sigma = 70

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.

So it is X when Z = -2.33.

Z = \frac{X - \mu}{\sigma}

-2.33 = \frac{X - 1600}{70}

X - 1600 = -2.33*70

X = 1436.9

The bulbs should be replaced each 1436.9 hours.

6 0
3 years ago
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