V₁ = 900.0 mL
T₁ = 27.0ºC + 273 = 300 K
V₂ = ?
T₂ = 132.0 + 273 = 405 K
V₁ / T₁ = V₂ / T₂
900.0 / 300 = V₂ / 405
300 x V₂ = 405 x 900.0
300 x V₂ = 364500
V₂ = 364500 / 300
V₂ = 1215 mL
hope this helps!
The nature of reactants, temperature, concentration, surface area and catalysts.
Answer:
2.68 cm^3
Explanation:
Density= Mass/Volume
so...
8.96 g/cm^3 = 24.01 g/ V
and then u solve so it would be 2.68 cm ^3
((:
Answer: Partial pressure of ammonia gas will be 0.36 atm.
Explanation: According to question we have partial pressure values of hydrogen and nitrogen gas with total pressure exerted by the all gases which hydrogen , nitrogen and ammonia. given
= 0.26 atm
= 0.28 atm
= ?
=0.90 atm
+ +=..(1)
putting values in (1)
0.26 + 0.28 + = 0.90
= 0.36 atm