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Whitepunk [10]
3 years ago
15

A shiny, smooth piece of black plastic and an identical piece of white plastic are exposed to visible light and sound waves. Whi

ch of the following is true about the different colors of plastic?
A. The white piece of plastic and the black piece of plastic will reflect both visible light and sound waves equally well.

B. The white piece of plastic will reflect both visible light and sound waves better than the black piece of plastic.

C. The white piece of plastic will reflect sound waves better than the black piece of plastic , but both pieces of plastic will reflect the same amount of visible light.

D. The white piece of plastic will reflect more visible light than the black piece of plastic, but both pieces of plastic will reflect sound waves in the same way.
Chemistry
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

The awnser is D

Explanation:

Since the black pieces absorb light better than white pieces, the white pieces will reflect light better. But since color doesn't affect sound, the sound waves are reflected the same.

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solution of a weak acid HA has initial concentration c and acid ionization constant Ka. To what concentration should the acid be
soldier1979 [14.2K]

Answer:

The concentration c is equal to Ka

Explanation:

The acid will ionize as observed in the following reaction:

HA = H+ + A-

H+ is the proton of the acid and A- is the conjugate base . The equation to calculate the Ka is as follows:

Ka = ([H+]*[A -])/[HA]

Initially we have to:

[H+] = 0

[A-] = 0

[HA] = c

During the change we have:

[H+] = +x

[A-] = +x

[HA] = -x

During balance we have:

[H+] = 0 + x

[A-] = 0 + x

[HA] = c - x

Substituting the Ka equation we have:

Ka = ([H+]*[A-])/[HA]

Ka = (x * x)/(c-x)

x^2 + Kax - (c * Ka) = 0

We must find c, having as [H+] = 1/2c. Replacing we have:

(1/2c)^2 + (Ka * 1/2 * c) - (c * Ka) = 0

(c^2)/2 + Ka(c / 2 - c) = 0

(c^2)/2 + (-Ka * c/2) = 0

c^2 -(c*Ka) = 0

c-Ka = 0

Ka = c

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3 years ago
Ethanol is added to gasoline because the oxygen it contains improves gasoline's burning efficiency. Its combustion reaction is g
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Answer:

A) The reaction is exothermic reaction

B) 46 gm CH3CH2OH  = 1236KJ

15.3 gm ch3ch2OH = 1236/46 x 15.3

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therefore  1 KJ = 0.239 K cal

so, 411.10 x 0.239 kcal

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c) 54 gm of H2O produced = 1236KJ

so, 42.7 gm H2O produced = 1236/54 x 42.7KJ

= 977.35 KJ released.

Explanation:

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5)HOCH2CH2OH

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This is also known as ethylene glycol. An increase in hydrogen bonds of a compound means an increase in the viscosity. Hydrogen bonds occur as a result of bonding with electronegative elements such as Oxygen, Nitrogen etc.

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