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Whitepunk [10]
3 years ago
15

A shiny, smooth piece of black plastic and an identical piece of white plastic are exposed to visible light and sound waves. Whi

ch of the following is true about the different colors of plastic?
A. The white piece of plastic and the black piece of plastic will reflect both visible light and sound waves equally well.

B. The white piece of plastic will reflect both visible light and sound waves better than the black piece of plastic.

C. The white piece of plastic will reflect sound waves better than the black piece of plastic , but both pieces of plastic will reflect the same amount of visible light.

D. The white piece of plastic will reflect more visible light than the black piece of plastic, but both pieces of plastic will reflect sound waves in the same way.
Chemistry
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

The awnser is D

Explanation:

Since the black pieces absorb light better than white pieces, the white pieces will reflect light better. But since color doesn't affect sound, the sound waves are reflected the same.

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4 years ago
The field lines around one end of a bar magnet are shown below.
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Answer:

<em>The correct option here would be the third one because it is true. </em>

Explanation:

The diagram shows a bar magnet that has lines that are parallel to each other and are pointing towards one side of the rectangle.

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A nuclear power plant operates at 40.0% efficiency with a continuous production of 1042 MW of usable power in 1.00 year and cons
Sergio039 [100]

Answer:

3.00 x 10^-11 joules / atom of U-235

Explanation:

We know that the formula for Power = Work done (w)/Time (t)

We need to get the joules from power , since Joules is the SI unit of work.

From the formula P = W/t

W = Power (P) * Time (t)

The SI unit for Time is seconds, hence we change 1 year in seconds

1yr * 365 days/yr * 24hrs/day * 60mins/hr * 60 secs/min = 31536000 secs

It was stated in the question that the plant operates at an efficiency of 40%,

Thus to get the true power we divide the power provided in the question by 0.4 or 40%

= X(0.4) = 1042MW

True Power X = 1042/0.4 = 2605MW

Thus true power = 2605 * 10^6 Watts

Now we have the time in seconds and true power in Watts, we then find the work done.

From our above formula P = W/t

W = P*t = (2605* 10^6) (31536000) =

Finally, we can solve for our energy (work):

P = W / T        PT = W = (2880x10^6) (31536000) = 8.22 x 10^16 joules

We then calculate the amount of energy released by only 1 single uranium-235 atom.

= 8.22 x 10^16 joules / 1.07x10^6 g U-235 (235 g / 1 mol)(1 mol/6.0210^23 atoms)

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