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emmainna [20.7K]
3 years ago
10

Charles traveled for 4 hours at 80 miles per hour. He then went 3 more hours at 65 miles per hour. Find the speed fro the entire

journey, rounded to the nearest tenth of a mile(PLEASE SHOW STEPS!!)
Mathematics
1 answer:
Akimi4 [234]3 years ago
5 0
1 hour is 15m
2 hour is 30m
3 hour is 65m
4 hour is 80m
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Answer:

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Step-by-step explanation:

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Which place value first determines which of the numbers 6.399 or 6.400 is the larger number?
kupik [55]

Comparing the numbers, it is found that the tenths value first determines which of the numbers 6.399 or 6.400 is the larger number.

The decimal numbers are 6.399 and 6.400.

  • The ones value for each is 6.
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The tenths digit is the <u>first in which there is a difference</u>, hence, it determines which of the numbers 6.399 or 6.400 is the larger number.

A similar problem is given at brainly.com/question/17248958

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2 years ago
candy that costs 31 cents per pound is mixed with candy that costs 46 cents per pound to obtain 50 pounds of candy that costs 40
photoshop1234 [79]

The amount of each type of candy (in pounds) that are mixed for the considered condition is: 20 pounds of first type of candy and 30 pounds of second type of candy.

<h3>How to form mathematical expression from the given description?</h3>

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically. For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4. If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.

For this case, we can assume the separate weights of each type of candies to be represented by variables.

Let we have:

  • x = weight (in pounds) of first type of candy whose cost is 31 cents per pound.
  • y = weight (in pounds)  of second type of candy whose cost is 46 cents per pound.

x pounds of first type of candy is mixed with y pounds of second candy.

The weight of the mixture = x + y = 50 pounds

The cost of the mixture = 40 cents per pound  = 40 \times 50 = 2000 cents

Cost of the mixture = cost of x pounds of first candy+ cost of y pounds of second candy = 31x + 46y
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Therefore, we got a system of two linear equations as:

x +y = 50\\31x + 46y =2000

From first equation, we get:

x = 50 -y

Substituting this value in second equation, we get:

31(50-y) + 46y =2000\\1550 + 15y = 2000\\15y = 450\\\\y = 450/15 = 30

Putting this value of y in equation for x, we get:

x = 50-y = 50-30 = 20

Thus, the amount of each type of candy (in pounds) that are mixed for the considered condition is: 20 pounds of first type of candy and 30 pounds of second type of candy.

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There are 5^5 students on the school and 5^2 students per class.


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