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lutik1710 [3]
2 years ago
15

The relationship between the number of pounds (lb) of peanuts and the price

Mathematics
1 answer:
lapo4ka [179]2 years ago
3 0
Most likely B because one pound is equal to 6 dollars. So i think it would be x= 1 and y= 6

So put the x as the dom and 6 as the num?
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Bob is buying the soccer team ice cream after the game today eight players my ice cream cookies in five please my ice cream cone
blsea [12.9K]

Answer:$18.75

Step-by-step explanation: first multiply 8 times 1.25 then multiply 5 times 1.75 then add both of your numbers and put the decimal point back

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3 years ago
adrian wants to buy a set of 6 sets of wireless headphones he does not want to spend over $360.how much can he spend per set of
Alex787 [66]

$60 is the absolute maximum he can spend!

3 0
3 years ago
Read 2 more answers
Find an equation for the graph
Elanso [62]

Answer:

y=6^x+0.612 - 4

Step-by-step explanation:

x = -4 ---> horizontal asymptote

m = 6 ---> use points (0, -1) and (1, 5)

Parent function of the graph: y=b^x

Our equation: y=6^x

Add alterations:

  1. Reflections = N/A
  2. Vertical & horizontal shifts = down 4
  3. Vertical & horizontal stretches = left approx 0.612

Final equation: y=6^x+0.612 - 4


6 0
2 years ago
Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB
Digiron [165]

Answer: The distace between midpoints of AP and QB is \frac{a}{8}.

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = \frac{AP}{2}

QB = \frac{AP}{2}

Substituing:

AP + 2*(\frac{AP}{2}) = a

2AP = a

AP = \frac{a}{2}

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = \frac{AP}{2}

QB = \frac{a}{2}*\frac{1}{2}

QB = \frac{a}{4}

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}

\frac{AP}{2} = \frac{a}{4}

<u>Midpoint of QB</u>:

\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}

\frac{QB}{2} = \frac{a}{8}

The distance is:

d = \frac{a}{4} - \frac{a}{8}

d = \frac{a}{8}

4 0
3 years ago
Solve the proportion below. x/29=2/5.8​
Bond [772]
X/29 = 2/5.8

(X) x (5.8). (2) x (29)

5.8x = 58

58/5.8

X = 10
5 0
3 years ago
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