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AURORKA [14]
3 years ago
6

Hans leaned a 17 ft ladder against his house. He placed the base of the ladder 8 ft from his house, and the top of the ladder re

ached the base of his window.
How high is the base of his window from the ground?
a^{2}+b^{2}=c^{2}
A.25
B.15
C.23
D.17
Mathematics
1 answer:
Fynjy0 [20]3 years ago
7 0

Answer:

b

Step-by-step explanation:

so 17 squared minus 8 squared is 225. the square root of 225 is 15

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Help please help help please please please
AnnZ [28]

Answer:

C. \frac{5}{4}

D. \frac{6}{7}

Step-by-step explanation:

C. 2 -  \frac{12}{16}

= 2 -  \frac{3}{4}

=  \frac{8 - 3}{4}

=  \frac{5}{4}

D. \frac{20}{22}  \times  \frac{33}{35}

=  \frac{10}{11}  \times  \frac{33}{35}

= 10 \times  \frac{3}{35}

= 2 \times  \frac{3}{7}

=  \frac{6}{7}

3 0
2 years ago
5. and 6. Show work for full credit please.
Delvig [45]

Answer:

2. YWX

Step-by-step explanation:

<T and <Y are congruent

<W and <W are congruent

<Z and <X are congruent

8 0
2 years ago
Use angle relationships to travel through the parallel maze following the prompts below.
musickatia [10]

Answer: 1,000,000,000,000,000,000,000,

Step-by-step explanation:

4 0
2 years ago
What is 5y+1 if y=6?
kipiarov [429]

Answer:

31

Step-by-step explanation:

5*6+1

30+1

31

4 0
3 years ago
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

6 0
2 years ago
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