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Svet_ta [14]
3 years ago
15

What is the solution to this system of linear equations?

Mathematics
1 answer:
OLEGan [10]3 years ago
3 0

Answer: To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations.

Step-by-step explanation: hope this helps

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Write 500.2 in word form
Rainbow [258]

Answer:

Five hundred point two

Step-by-step explanation:

500.2

That's a deimal.

The digit 5 is an hundred. Hence, we have

Five hundred point two

7 0
4 years ago
Solve the system by elimination<br><br> 3x-2y=3<br> 15x-4y=-3
stiv31 [10]

Answer:

x=-1

y=-3

Step-by-step explanation:

3x-2y=3(1)

5.(1) <=> 15x-10y=15 (2)

15x-4y=-3 (3)

(2)-(3) <=> -6y=18

4 0
3 years ago
A probability experiment is conducted in which the sample space of the experiment is Upper S equals StartSet 1 comma 2 comma 3 c
kkurt [141]

Answer:

Step-by-step explanation:

According to the mentioned information, the sample space of the experiment is as follows: S= {7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18} The outcomes of the event E are as follows: E = {7, 8, 9, 10, 11, 12} Therefore, the outcomes of Ec can be calculated as:

E^{c} = {xlx ∈ S , x ∉ E}

Ec = {13, 14, 15, 16, 17, 18}

The outcomes of E^{c} are {13, 14, 15, 16, 17, 18} .

The obtained outcomes of the set Ec are {13, 14, 15, 16, 17, 18} . These are calculated by subtracting the outcomes of the event E from the elements of sample space S.

kindly check the image below for the concluding part if the solution to the question

6 0
3 years ago
Consider the initial value problem:
Inessa [10]

Answer:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

Step-by-step explanation:

The given initial value problem is;

y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2

Let

u(t)=y(t)----(2)\\v(t)=y'(t)----(3)

Differentiating both sides of equation (1) with respect to t, we obtain:

u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)

Differentiating both sides of equation (2) with respect to t gives:

v'(t)=y''(t)----(6)

From equation (1),

y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)

Putting t=0 into equation (2) yields

u(0)=y(0)\\\implies u(0)=-5

Also putting t=0 into equation (3)

u'(0)=y'(0)\\u'(0)=2

The system of first order equations is:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

3 0
4 years ago
What is the Greatest Common Factor of 12 and 36? (1 point)
madreJ [45]

Answer: D) 12

The factors of 12 are: 1, 2, 3, 4, 6, 12

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The greatest common factor is 12.

6 0
3 years ago
Read 2 more answers
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