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Burka [1]
4 years ago
13

What is the horizontal asymptote??? Math 3!! 10 points HELP NEEDED

Mathematics
1 answer:
Ymorist [56]4 years ago
8 0

Answer:

no horizontal asymptote

Step-by-step explanation:

When the degree of the numerator > degree of the denominator there is no horizontal asymptote but there is a slant asymptote.

Dividing the numerator by the denominator gives

\frac{x^2-x-6}{x+4} = x - 5 + \frac{14}{x+4}

There is a slant asymptote with equation y = x - 5

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exis [7]

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Step-by-step explanation:

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3 years ago
What is the perimeter of ABC with vertices A(-2,9), B(7,-3), and C(-2,-3) and in the coordinate plain?
RSB [31]

Answer:

Step-by-step explanation:

A - C = ( -2, 9) - (- 2 -3) 

= ( 0, 12) 

AC = 12 

B - C = (7 - 3) - ( - 2 -3) 

= (9, 0) 

BC = 9 

ABC is a right -angled triangle with AC as the hypotenuse 

AC = sqrt( 9^2 + 12^2) 

= sqrt(81 + 144) 

= srqt(225) 

= 15 

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5 0
4 years ago
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3 years ago
3x√64= please help meee
Mumz [18]

Answer:

I think the answer is 2.7

Step-by-step explanation:

3x√64

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4 0
3 years ago
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X^2+14=9x
trasher [3.6K]
X squared +14=9x
Square both sides and you get
X+14=3x subtract 14 from both sides
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X=3x-14 subtract 3x

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7 0
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