The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
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Given:
square shape
Perimeter 28 feet
Find its area
A square has 4 equal sides, so perimeter is 4a
Perimeter = 4a
28 ft = 4 a
28 ft / 4 = a
7 = a
One side of the the square is 7 ft.
Area of a square is the measure of one side raised to the power of 2.
A = a²
A = (7 ft)²
A = 49 ft²
The equation for a quadratic is as follows:
y = ax^2+bx+c
The first variable “a” determines whether the parabola opens up or down
The squared allows the equation to look like the parabola swoop when graphed.
The c term is the constant term
Answer:
12
Step-by-step explanation:
Using the pythagorean theorem, we know that a^2+ b^2=c^2
In our case, we know b, which is 5 and c which is 13.
If we plug that into the equation, we get a^2+ 5^2 = 13^2
Next, we simplify the equation. a^2 + 25 = 169
Then we subtract 25 from 169. 169 - 25 = 144.
Lastly, we do the square root of 144 and we get 12 which is the missing side.
Answer:
x=2
Step-by-step explanation:
This is a one-to-one relationship, so when the output (range) is 4, the input (domain) is 2
