Help with thsi pls show work

Mathematics

1 answer:

Lerok [7]3 years ago

4 0

Answer:

Step-by-step explanation:

I answered on this question 7 hours ago too!!!!!!

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What are the y- coordinates of b

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A sign at the entrance to a bridge reads: Maximum allowable weight 2.25 tons Jason truck weighs 2150 pounds how much additional

Bezzdna [24]

Hi there!

First, we must know that 1 ton=2000 pounds

2.25×2000=4500 pounds (maximum allowable weight)
4500-2150=2350

Therefore Jason can carry 2350 pounds more weight if he wanted to.

Hope this helps!

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a person kicks a ball from the ground into the air with an initial upward velocity of 8 feet per second. what is the maximum hei

KengaRu [80]

Chech the picture below.

if the person kicked it from the ground, that means its initial height is 0.

it reaches its maximum height at the y-coordinate of its vertex, and it will hit the ground when y = 0, as you see in the picture.

$\bf ~~~~~~\textit{initial velocity}
\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}
\\\\
h(t) = -16t^2+v_ot+h_o
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{8}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{0}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}
\\\\\\
h(t)=-16t^2+8t+0$

now let's find the y-coordinate of its vertex

$\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+8}t\stackrel{\stackrel{c}{\downarrow }}{+0}
\qquad \qquad 
\left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)
\\\\\\
\left(\qquad ,~~0-\cfrac{8^2}{4(-16)} \right)\implies (\quad ,~0+1)\implies (\quad ,~1)$

when will it hit the ground?

$\bf \stackrel{h(t)}{0}=-16t^2+8t\implies 16t^2-8t=0\implies 8t(2t-1)=0
\\\\\\
8t=0\implies \stackrel{\textit{0 seconds when it took off first}}{t=0}
\\\\\\
2t-1=0\implies 2t=1\implies \stackrel{\textit{half a second later it when it came back down}}{t=\cfrac{1}{2}}$

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