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Anuta_ua [19.1K]
3 years ago
5

Mikela claims that the sum of any two numbers is greater than the larger of the two numbers. Jim claims that the sum of any

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

Step-by-step explanation:

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Liam buys a rosebush during the sale. If the original price was $30, how much does Liam pay?
kobusy [5.1K]

Answer:

Liam pays $24

Step-by-step explanation:

20% off = 20÷100= 1/5

1/5 × $30 = $6

$30 - $6 =$24

3 0
2 years ago
Which option for college funding can parents start when children are still very young? College savings account scholarship work-
kap26 [50]

Answer:

Your answer would be A: "college savings account."

Step-by-step explanation:

Got it right on edge.

6 0
3 years ago
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What is true about all points on the y-axis in Quadrant I?
Eva8 [605]

Answer:

All have an x-coordinate of 0.

and

All are directly above the origin.

These answers are correct

Step-by-step explanation:

i did the quiz/or/assignment

6 0
3 years ago
Question: A box of chocolates contains square chocolates, which weigh 10 g each, and round chocolates, which weigh 8 g each. The
Viktor [21]

Answer: the box contained 9 square chocolates and 15 round chocolates.

Step-by-step explanation:

Let x represent the number of square chocolates contained in the box.

Let y represent the number of round chocolates contained in the box.

The box of chocolates contains square chocolates, which weigh 10g each and round chocolates which weigh 8g each. The combined weight of all the chocolates is 210g. It means that

10x + 8y = 210- - - - - - - - - - -1

The number of round chocolates is 3 less than twice the number of square chocolates. It means that

y = 2x - 3

Substituting y = 2x - 3 into equation 1, it becomes

10x + 8(2x - 3) = 210

10x + 16x - 24 = 210

26x = 210 + 24

26x = 234

x = 234/26

x = 9

y = 2x - 3 = 2 × 9 - 3

y = 18 - 3

y = 15

3 0
3 years ago
Solve for h<br> -8 &lt; -4h + 20
Vladimir [108]

Answer:

h < 7

Step-by-step explanation:

-8 < -4h + 20

4h < 28 / : 4

h < 7

5 0
3 years ago
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