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Rufina [12.5K]
3 years ago
11

The diameter of your bicycle wheel is 34 inches. What is it’s radius

Mathematics
2 answers:
natka813 [3]3 years ago
4 0

The diameter of a circle (or in this case a bicycle wheel) is how long it is from one side of the circle striaght across to the other side.  The radius is half the diameter.  So if the diameter is 34, then the radius would be 17.

Vlad [161]3 years ago
4 0

17 inches

Diameter = 2 * radius

So you can rewrite that as

Radius = diameter / 2

34/2=17

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Which of the expressions below can be factored using the difference of<br> squares method?
zlopas [31]

Answer:

<em>The second choice is correct. It can be factored as:</em>

9x^2-16y^2=(3x-4y)(3x+4y)

Step-by-step explanation:

<u>The Difference of Squares Method for Factoring</u>

The expression:

a^2-b^2=(a-b)(a+b)

Is a widely used method to factor binomials that are expressed as the subtraction of two perfect squares.

The condition for a binomial to be factored by using this method is that both terms must have an exact square root and they must be subtracted.

The last two choices are not valid because they are not a subtraction but an addition.

The first choice is not valid because none of the terms is a perfect square.

The second choice is correct. It can be factored as:

9x^2-16y^2=(3x-4y)(3x+4y)

4 0
3 years ago
Which score indicates the highest relative position? I. A score of 2.6 on a test with X = 5.0 and s = 1.6 II. A score of 650 on
Zanzabum

Answer:

A score of 2.6 on a test with \bar X = 5.0 and s = 1.6 and A score of 48 on a test with \bar X = 57 and s = 6 indicate the highest relative position.

Step-by-step explanation:

We are given the following:

I. A score of 2.6 on a test with \bar X = 5.0 and s = 1.6

II. A score of 650 on a test with \bar X = 800 and s = 200

III. A score of 48 on a test with \bar X = 57 and s = 6

And we have to find that which score indicates the highest relative position.

For finding in which score indicates the highest relative position, we will find the z score for each of the score on a test because the higher the z score, it indicates the highest relative position.

<u>The z-score probability distribution is given by;</u>

              Z = \frac{X-\bar X}{s} ~ N(0,1)

where, \bar X = mean score

            s = standard deviation

            X = each score on a test

  • <u>The z-score of First condition is calculated as;</u>

Since we are given that a score of 2.6 on a test with \bar X = 5.0 and s = 1.6,

So,  z-score = \frac{2.6-5}{1.6} = -1.5  {where \bar X = 5.0 and s = 1.6 }

  • <u>The z-score of Second condition is calculated as;</u>

Since we are given that a score of 650 on a test with \bar X = 800 and s = 200,

So,  z-score = \frac{650-800}{200} = -0.75  {where \bar X = 800 and s = 200 }

  • <u>The z-score of Third condition is calculated as;</u>

Since we are given that a score of 48 on a test with \bar X = 57 and s = 6,

So,  z-score = \frac{48-57}{6} = -1.5  {where \bar X = 57 and s = 6 }

AS we can clearly see that the z score of First and third condition are equally likely higher as compared to Second condition so it can be stated that <u>A score of 2.6 on a test with </u>\bar X<u> = 5.0 and s = 1.6</u> and <u>A score of 48 on a test with </u>\bar X<u> = 57 and s = 6 </u> indicate the highest relative position.

7 0
4 years ago
Fill in the other coordinate for the line y=23x+3 y = 2 3 x + 3 : (3, )
Igoryamba
23(3) +  3

= 72

Why do you write 2 equations?

5 0
4 years ago
Read 2 more answers
This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
harina [27]
L(x,y,z,\lambda)=8x+8y+4z+\lambda(4x^2+4y^2+4z^2-36)

L_x=8+8\lambda x=0\implies 1+\lambda x=0
L_y=8+8\lambda y=0\implies 1+\lambda y=0
L_z=4+8\lambda z=0\implies 1+2\lambda z=0
L_\lambda=4x^2+4y^2+4z^2-36=0\implies x^2+y^2+z^2=9

yL_x=y+\lambda xy=0
xL_y=x+\lambda xy=0
\implies yL_x-xL_y=y-x=0\implies y=x

2zL_x=2z+2\lambda xz=0
xL_z=x+2\lambda xz=0
\implies 2zL_x-xL_z=2z-x=0\implies x=2z

2zL_y=2z+2\lambda yz=0
yL_z=y+2\lambda yz=0
\implies 2zL_y-yL_z=2z-y=0\implies y=2z

x=y=2z\implies x^2+y^2+z^2=9\iff 4z^2+4z^2+z^2=9z^2=9\implies z=\pm1

z=\pm1\implies y=x=\pm2

So we have two critical points, (2, 2, 1) and (-2, -2, -1), which respectively give a max of 36 and a min of -36.
5 0
3 years ago
HURRY 50 POINYS OKAY
never [62]
What are we supposed to review? There are no specific answers?
3 0
2 years ago
Read 2 more answers
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