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3 years ago

The diameter of your bicycle wheel is 34 inches. What is it’s radius

2 answers:

4 0

The diameter of a circle (or in this case a bicycle wheel) is how long it is from one side of the circle striaght across to the other side. The radius is half the diameter. So if the diameter is 34, then the radius would be 17.

Vlad [161]3 years ago

4 0

17 inches

Diameter = 2 * radius

So you can rewrite that as

Radius = diameter / 2

34/2=17

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Y=-3x+5 5x-5y=-3by substitution

Reptile [31]

Answer:

Y = − 3 x + 5 5 x − 5 y = - 3

Step-by-step explanation:

the question is already substituted

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3 years ago

Shauna bought a flat cardboard box

bonufazy [111]

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3 years ago

Find x of the triangle

sukhopar [10]

Answer:

Step-by-step explanation:

altitude = sqrt(6*8) = 4*sqrt(3)

Use the Pythagorean Theorem to derive x

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3 years ago

I'm lost.. How do you even start it???

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$2x+y=4\\
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3 years ago

Read 2 more answers

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let X = number of students who read above the eighth grade level.

(a)

A sample of n = 269 students are selected. Of these 269 students, X = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

$\hat p=\frac{X}{n}=\frac{224}{269}=0.8327$

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

$1-\hat p=1-0.8327$

$=0.1673$

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

n = 709

X = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

$\hat q=1-\hat p$

$=1-\frac{X}{n}$

$=1-\frac{546}{709}$

$=0.2299\\\approx 0.229$

The critical value of z for 95% confidence interval is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for the population proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)$

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

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3 years ago