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malfutka [58]
3 years ago
14

Consider two circular swimming pools. Pool A has a radius of 22 feet, and Pool B has a diameter of 13.6 meters. Complete the des

cription for which pool has a greater circumference. Round to the nearest hundredth for each circumference. 1 foot ? 0.305 meters The diameter of Pool A is ... meters. So, the diameter of Pool... Is greater, and the circumference is... By... meters.
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

See below.

Step-by-step explanation:

Diameter of pool A = 2 * radius = 2 * 22

= 44 feet

= 44 * 0.305 = 13.42 meters.

The diameter of Pool B ( 13. 6 m)  is greater than the diameter of Pool A.

The circumference of Pool A is 13.42 * pi = 42.16 m and that of B is 42.73 m, so that  the circumference of Pool B is greater than that of Pool A by

0.57 m.

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2(5x - 3) - 4 = x + 4 solve for x and show work
Katen [24]

Answer:

x= 14/9 = 1 5/9

Step-by-step explanation:

Use the distributive property to multiply 2 by 5x−3.

2(5x−3)−4=x+4

Subtract 4 from −6 to get −10.

10x−6−4=x+4

Subtract x from both sides

10x−10=x+4

Combine 10x and −x to get 9x.

10x−10−x=4

Add 10 to both sides.

9x−10=4

Divide both sides by 9.

x=  14/9

Please mark brainliest.

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4 0
3 years ago
Read 2 more answers
On a coordinate plane, a point is at (negative 4, negative 4) and (negative 4, negative 10).
Valentin [98]

Answer:

Option C.

Step-by-step explanation:

Hey there!

The points are; (-4,-4) and (-4,-10).

<u>Use </u><u>distance</u><u> formula</u><u>.</u>

d =  \sqrt{ {(x2 - x1)}^{2} +  {(y2 - y1)}^{2}  }

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d =  \sqrt{ {( - 4 + 4)}^{2}  + (  { - 10  + 4)}^{2} }

~ Simplify it.

d =  \sqrt{ {0}^{2} + ( { - 6)}^{2}  }

d =  \sqrt{36}

Therefore, distance between the points is 6 units.

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6 0
3 years ago
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jeka57 [31]

Answer:??????????????????

Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

First you do 1482/7 which gives you an average for each day (211.7)

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6 0
3 years ago
how are the ordered pairs 4,9 and 4,-9 similar, and how are they different? Are the two points related by a reflection over an a
eduard
(4,9) is in quarter I and (4,-9) is in quarter IV of the graph. (4,-9) is the point (4,9) reflected over the x-axis. they are similar bc both have 4 as their x coordinate.
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