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malfutka [58]
3 years ago
14

Consider two circular swimming pools. Pool A has a radius of 22 feet, and Pool B has a diameter of 13.6 meters. Complete the des

cription for which pool has a greater circumference. Round to the nearest hundredth for each circumference. 1 foot ? 0.305 meters The diameter of Pool A is ... meters. So, the diameter of Pool... Is greater, and the circumference is... By... meters.
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

See below.

Step-by-step explanation:

Diameter of pool A = 2 * radius = 2 * 22

= 44 feet

= 44 * 0.305 = 13.42 meters.

The diameter of Pool B ( 13. 6 m)  is greater than the diameter of Pool A.

The circumference of Pool A is 13.42 * pi = 42.16 m and that of B is 42.73 m, so that  the circumference of Pool B is greater than that of Pool A by

0.57 m.

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Convert 9/5 and -4/5 to decimal form 
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2 years ago
A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther
mariarad [96]
<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\

Therefore, on checking, we observe that,

a_{n}=a_{n-1}+(n-1)^{2}

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

<u>At, </u>

<u>n = 1</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0

which is true.

<u>At, </u>

<u>n = 2</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1

Which is also true.

<u>At, </u>

<u>n = 3</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5

Which is true.

<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

This is also true at the given value of 'n'.

<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

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