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2 years ago

13

A car's speed 3 seconds after accelerating from rest at 2 m/s^2 is?

1 answer:

Anarel [89]2 years ago

5 0

Answer:

After 3 seconds, the velocity is 4.5+3×1.5=9 m/s.

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Consult Multiple-Concept Example 11 for background material relating to this problem. A small rubber wheel on the shaft of a bic

Papessa [141]

Answer:

$Emf=24.4V$

Explanation:

From the question we are told that:

Angular speed $\omega=40*\omega'$

Radius $r=0.33m$

No. Turns $N=163$

Area $A= 3.23 * 10^{-3} m^2$

Magnetic field. $B=0.0948T$

Acceleration $a=0.60m/s^2$

Time $t=6.72s$

Generally the equation for momentum is mathematically given by

$\omega'=\omega_o+\frac[a}{r}t$

$\omega'=0+\frac{0.60}{0.33}*6.72$

$W=12.22rad/s^2$

Therefore

$\omega=Aw$

$\omega=12.22*40$

$\omega=488.7rads/s$

Generally the equation for Peak emf is mathematically given by

$Emf=NBA \omega$

$Emf=163*0.0948* 3.23 * 10^{-3} m^2*488.7rads/s$

$Emf=24.4V$

3 0

3 years ago

A cruise ship makes its way from one island to another. The ship is in motion compared with which reference point?

Georgia [21]

The anwser is c there is a light house near by

7 0

3 years ago

Let's apply Snell's law to the refraction of light across a water–air interface. Suppose you kneel beside the fishpond in your b

Nataliya [291]

Answer:

The angle of refraction is 41.68°.

Explanation:

The refractive index for water is $n_2 = 1.333$ , and for air $n_1 = 1.00$ : the angle of light with the normal is $90^o-60^o = 30^o$ ; therefore Snell's law gives

$n_1sin(\theta_1)= n_2sin(\theta_2)$

$1.00*sin(\theta_1) = 1.33 sin(30^o)$

$sin (\theta_1) = \dfrac{1.33sin(30^o)}{1.00}$

$sin (\theta_1) = 0.665$

$\theta _1 = sin^{-1}(0.665)$

$\boxed{\theta_1 = 41.68^o}$

4 0

3 years ago

Please help! It’s urgent

Elza [17]

What do you want help with

7 0

3 years ago

Read 2 more answers

Why is the absolute magnitude of some stars greater than their apparent magnitude

SSSSS [86.1K]

<span>answer under the link: http: //briskrange.com/7gAl</span>

6 0

4 years ago