Question: A loader sack of total mass
is l000 grams falls down from
the floor of a lorry 200 cm high
Calculate the workdone by the
gravity of the load.
Answer:
19.6 Joules
Explanation:
Applying
W = mgh........................ Equation 1
Where W = Workdone by gravity on the load, m = mass of the loader sack, h = height, g = acceleration due to gravity
From the question,
Given: m = 1000 grams = (1000/1000) kilogram = 1 kg, h = 200 cm = 2 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
W = (1×2×9.8)
W = 19.6 Joules
Hence the work done by gravity on the load is 19.6 Joules
The main requirement for a good conductor of electricity is to have a lot of valence electrons. Valence electrons are the electrons of the outer shells of atoms not bound with other atoms (for example through covalent bounds). These electrons are "free to escape" as soon as an electric field with enough intensity is applied to the material, and therefore these electrons will be free to move in the material producing an electric current.
Answer:
The maximum voltage is 41.92 V.
Explanation:
Given that,
Peak voltage = 590 volts
Suppose in an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is 
.
We need to calculate the resonance frequency
Using formula of frequency
Put the value into the formula
We need to calculate the maximum current
Using formula of current
Impedance of the circuit is
At resonance frequency 
We need to calculate the maximum voltage
Using ohm's law
Hence, The maximum voltage is 41.92 V.
<span>C. It is the difference in electrical potential energy between two places in an electric field.</span>
Florine is special becaus Florine is at the highest value of electronegative value with 4.0
