Answer: Context Effect
Explanation:
<u>Context effect</u> refers to <u>the influence that external factors (the environment, for example) have on the perception of a stimulus</u>. This is a well-known aspect of cognitive psychology.
In fact, the situation stated in this question is a good example: It is not the same to observe the Moon with a naked eye and taking into account factors such as cloudiness, dust and whatever is surrounding this view that have effects on the observation; than observing this same Moon with a narrow tube in which our eyes focus only on the lunar surface, without taking into account the rest that surrounds that horizon.
Answer:
curves downward, below the initial velocity vector.
Explanation:
Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).
Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.
Answer:
i can't see the picture, it is blocked off, can you write down your question?
Explanation:
Answer:
The pressure in a gas container is 839.44mmHg
Explanation:
Density of Mercury = 13.56g/cm³ = 13556kg/m³
hρg/ P₀
where, g= acceleration due to gravity, 10m/s²
h= height= 8.6cm = 0.086m
= hρg/ P₀
= 0.086 × 13556 × 10
= 11658.16 kgm/ m²s²
= 11658.16 N/m² = 11658.16pa
= 87.4434mmHg
where 1 torr = 1mmHg
= 752torr = 752mmHg
= 752 + 87.4434
= 839.44mmHg
Answer:10m/s
Explanation:
M=mass of gun=4kg
U=recoil velocity of gun
m=mass of bullet=0.1kg
V=velocity of bullet=400m/s
M x U=m x V
4 x U=0.1 x 400
4xU=40
Divide both sides by 4
(4xU)/4=40/4
U=10m/s
Recoil velocity=10m/s
