Answer:
The ionization equation is
⇄
(1)
Explanation:
The ionization equation is
⇄
(1)
As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.
The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,
![Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}](https://tex.z-dn.net/?f=Ka%20%3D%20%5Cfrac%7B%5BHPO_%7B4%7D%5E%7B-2%7D%5D%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BH_%7B2%7DPO_%7B4%7D%5E%7B-%7D%5D%20%5BH_%7B2%7DO%5D%7D%20%3D%206.2x10%5E%7B-8%7D)
The pKa is
![-Log (Ka) = -Log (6.2x10^{-8}) = 7.2](https://tex.z-dn.net/?f=-Log%20%28Ka%29%20%3D%20-Log%20%286.2x10%5E%7B-8%7D%29%20%3D%207.2)
The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.
In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.
If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1) moves to the left neutralizing the excess proton concentration.
BIOSPHERE AND LITHOSPHERE INTERACTION
1)How many molecules are
there in 2.3 grams of NH
SO.?
Answer:
1.69 x 10^22
Answer:
2Al + 6HCl -----> 2AlCl3 + 3H2
Reaction of acid with metals
Cu(OH)2. -----> H2O. + CuO
Dissociation of coper hydroxide / dissociation of base
Explanation: