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Pie
3 years ago
13

Categorize them by Metal, Nonmetal, Metalloid

Chemistry
1 answer:
laila [671]3 years ago
6 0

Answer:

METAL: found in periodic table, lithium, shiny, lose electrons easily, good conductor, elements

NONMETAL: brittle, ductile, semimetals, found in periodic table, often gain electrons, semiconductors, carbon, shiny, poor conductor, elements

METALLOID: solid, non- ductile, malleable, found in periodic table, silicon, shiny, can be liquids, elements

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70 mL of liquid (density = 0.85 g/mL) is added to a graduated cylinder that has a mass of 60.75 g. what is the mass of the cylin
BabaBlast [244]
According to the density of the liquid, we can get the mass of liquid is 70*0.85=59.5 g. So the total mass is 59.5+60.75=120.25 g.
8 0
3 years ago
Name 8 ways why landfill is bad for earth
Sergio039 [100]

Answer:

1.Creates environmental hazards

2.Can contribute to global warming processe

3.Can pollute harmful and toxic things in the air

4.has harmful gases that can hurt the environment including the water and soil

5.A waste of space that is taking up the earth

6.full of rubbish and toxins that can effect the environment

7.can hurt humans and animals because of the toxic chemicals produced in the air

8.Make the land soil weaker because of the bad toxins and chemicals

4 0
3 years ago
PLS HELP Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement
iVinArrow [24]

Answer:

you are already right d

Explanation:

3 0
3 years ago
In a titration, 25.9 mL of 3.4 x10^-3 M Ba(OH)2 neutralized 16.6 mL of HCL solution. What is the molarity of the HCL solution?
san4es73 [151]
First, We have to write the equation for neutralization:
Ba(OH)2 + 2HCl → BaCl2 + 2H2O 
so, from the equation of neutralization, we can get the ratio between Ba(OH)2 and HCl. Ba(OH)2 : HCl = 1:2 
- We have to get the no.of moles of Ba(OH)2 to do the neutralization as we have 25.9ml of 3.4 x 10^-3 M Ba(OH)2.
So no.of moles of Ba(OH)2 = (25.9ml/1000) * 3.4x10^-3 = 8.8 x 10^-5 mol
and when Ba(OH)2 : HCl = 1: 2 
So the no.of moles of HCl = 2 * ( 8.8x10^-5) =  1.76 x 10^-4 mol

So when we have 1.76X10^-4 Mol in 16.6 ml (and we need to get it per liter)
∴ the molarity = no.of moles / mass weight
                        = (1.76 x 10^-4 / 16.6ml)* (1000ml/L) = 0.0106 M Hcl

4 0
3 years ago
Which of the following reagents is/are likely to be used to form the Britton–Robinson buffer solution used in the experiment?
Ierofanga [76]

Answer:

I. A polyprotic, weak acid

II. Na2HPO4

Explanation:

Buffer solutions are those that, upon the addition of an acid or base, are capable of reacting by opposing the part of the basic or acid component to keep the pH fixed.

Buffers consist of hydrolytically active salts that dissolve in water. The ions of these salts are combined with acids and alkalis. These hydrolytically active salts are the products that result from the reaction between weak acids and strong alkalis such as calcium carbonate (from carbonic acid and calcium hydroxide) or between strong acids and weak alkalis such as ammonium chloride (a from hydrochloric acid and ammonium hydroxide).

A buffer acid reacts when a weak acid or weak base is combined with its corresponding hydrolytic salt in a water solution, a buffer system called a buffer is formed. As in this case a weak polyrotic acid with Na2HPO4, which allows the solution to be maintained at a pH of 3.8 against small aggregate amounts of both acid and base, thus favoring the reaction at a pH of 3.8

A buffer system is not always appropriate, because the ions of some hydrolytic salts can, for example, damage organisms that come into contact with it.

4 0
3 years ago
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