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kompoz [17]
3 years ago
7

Conclusion Questions:

Chemistry
1 answer:
Lerok [7]3 years ago
5 0
That’s the question?
You might be interested in
Complete the following radioactive decay problem.<br>222 86 RN to 4 2 HE + ?​
Andreas93 [3]

Answer:

₈₆²²²Rn    →   ₈₄Po²¹⁸  +  H₂⁴

Explanation:

The given nuclear reaction shows alpha decay.

₈₆²²²Rn    →   ₈₄Po²¹⁸  +  H₂⁴

Properties of alpha radiations:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4  and atomic number less than 2 as compared to parent atom the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

₉₂U²³⁸   →   ₉₀Th²³⁴  + ₂He⁴  + energy

8 0
3 years ago
What data do you need to determine the specific heat capacity of a substance?
strojnjashka [21]

Speific heat capacity is measured with the aid of determining how a whole lot warmth electricity is needed to increase one gram of a substance one digree Celsius. The Speific heat capacity of water is 4.2 joules per gram per degree Celsius or 1 calorie in step with gram per digree Celsius.

The specific heat capacity is defined as the amount of heat (J) absorbed consistent with unit mass (kg) of the substance while its temperature increases 1 ok (or 1 °C), and its units are J/(kg k) or J/(kg °C).

Factors specific heat capacity relate to are temperature and strength.

The Speific heat capacity C can be measured as q = mC∆T

Or, C = q/m∆T

where,

C is the specific heat capacity

q is the quantity of heat required

m is the mass

∆T is the change in temperature

As a consequence so as to degree the specific heat capacity we need to recognize mass of the substance, quantity of heat lost or gain by the substance and the exchange in temperature.

Lear more about Speific heat capacity here: brainly.com/question/17162473

#SPJ4

6 0
1 year ago
2) Examine the molecules below.<br> Circle the molecules that can also be classified as compounds.
sergejj [24]

Answer:

3rd

Explanation:

its the way they look

4 0
2 years ago
What is a mol in chemistry
Snowcat [4.5K]
Molecular weight it stands for molecular weight






6 0
3 years ago
Calculate the energy required to heat 406.0mg of cyclohexane from 33.5°C to 38.9°C . Assume the specific heat capacity of cycloh
N76 [4]

Answer:

Q = 4.056 J

Explanation:

  • Q = m<em>C</em>ΔT

∴ m = 406.0 mg = 0.406 g

∴ <em>C </em>= 1.85 J/g.K

∴ T1 = 33.5°C ≅ 306.5 K

∴ T2 = 38.9°C = 311.9 K

⇒ ΔT = 311.9 - 306.5 = 5.4 K

⇒ Q = (0.406 g)(1.85 J/gK)(5.4 K)

⇒ Q = 4.056 J

6 0
3 years ago
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