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kompoz [17]
3 years ago
7

Conclusion Questions:

Chemistry
1 answer:
Lerok [7]3 years ago
5 0
That’s the question?
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How much of a 0.250 M lithium hydroxide is required to neutralize 20.0 mL of 0.345M chlorous acid?
Bumek [7]

Answer:

27.6mL of LiOH 0.250M

Explanation:

The reaction of lithium hydroxide (LiOH) with chlorous acid (HClO₂) is:

LiOH + HClO₂ → LiClO₂ + H₂O

<em>That means, 1 mole of hydroxide reacts per mole of acid</em>

Moles of  20.0 mL = 0.0200L of 0.345M chlorous acid are:

0.0200L ₓ (0.345mol / L) = <em>6.90x10⁻³ moles of HClO₂</em>

To neutralize this acid, you need to add the same number of moles of LiOH, that is 6.90x10⁻³ moles. As the LiOH contains 0.250 moles / L:

6.90x10⁻³ moles ₓ (1L / 0.250mol) = 0.0276L of LiOH =

<h3>27.6mL of LiOH 0.250M</h3>
6 0
3 years ago
Is it possible to have boiling ice water?
Virty [35]

Answer:

Possibly

Explanation:

Cold water does not boil faster than hot water. ... As a result, cold water will be absorbing heat faster while it is still cold; once it gets up to the temperature of hot water, the heating rate slows down and from there it takes just as long to bring it to a boil as the water that was hot to begin with.

8 0
3 years ago
Which type of chemical reaction occurs in Ca+CI2 CaCI2
dimaraw [331]
Ca + Cl2 = CaCl₂


A synthesis <span>reaction.</span>
3 0
4 years ago
PLEASE ANSWER THESE QUESTIONS FOR 21 POINTS AND A BRAINLIEST, KEEP IN MIND THESE QUESTIONS ARE VERY IMPORTANT AND WILL DETERMINE
Katena32 [7]
Sexual Reproduction requires two parents.
6 0
3 years ago
What is the mass of 8.2 * 10^11 molecules of this compound
Goryan [66]

Answer:

It depends what the compound is.

Explanation:

You need to use Avogadro's number (6.22*10^23) to convert the number of molecules of a compound to moles of the compound. From there, you can use the molar mass of the compound (grams per mole) to get the mass. You can get the molar mass by googling "molar mass of [compound]" or calculate it yourself using the periodic table.

So: 8.2*10^11 molecules of the compound * (1 mole of the compound/6.022*10^23 molecules of the compound) * (# of grams/1 mole of the compound)

7 0
3 years ago
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