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3 years ago

50points+brainliest for the one who solved this.It's not a homework but I am curious

Mathematics

1 answer:

4vir4ik [10]3 years ago

4 0

Answer:

1/xy

Step-by-step explanation:

Simplify the numerator:

(2x - y)/(2x + y) + (2x + y)/(3y - 6x) + 8xy/(12x² - 3y²) =
(2x - y)/(2x + y) - (2x + y)/3(2x - y) + 8xy/3(2x + y)(2x - y) =
[3(2x - y)² - (2x + y)² + 8xy] / [3(2x + y)(2x - y)] =
[12x² - 12xy + 3y² - 4x² - 4xy - y² + 8xy] / [3(2x + y)(2x - y)] =
[8x² - 8xy + 2y²] / [3(2x + y)(2x - y)] =
2{2x - y)² / [3(2x + y)(2x - y)] =
2(2x - y) / [3(2x + y)]

Simplify the denominator:

(4x²y - 2xy²) / (6x + 3y) =
2xy(2x - y) / [3(2x + y)]

Now simplify the remainder of the expression:

2(2x - y) / [3(2x + y)] × [3(2x + y)]/[2xy(2x - y}] =
1/xy

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Answer:

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Step-by-step explanation:

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Consider the figure attached.

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3 years ago

50points+brainliest for the one who solved this.It's not a homework but I am curious​

50points+brainliest for the one who solved this.It's not a homework but I am curious