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andre [41]
3 years ago
6

50points+brainliest for the one who solved this.It's not a homework but I am curious​

Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0

Answer:

  • 1/xy

Step-by-step explanation:

<u>Simplify the numerator:</u>

  • (2x - y)/(2x + y) + (2x + y)/(3y - 6x) + 8xy/(12x² - 3y²) =
  • (2x - y)/(2x + y) - (2x + y)/3(2x - y) + 8xy/3(2x + y)(2x - y) =
  • [3(2x - y)² - (2x + y)² + 8xy] / [3(2x + y)(2x - y)] =
  • [12x² - 12xy + 3y² - 4x² - 4xy - y² + 8xy] / [3(2x + y)(2x - y)] =
  • [8x² - 8xy + 2y²] / [3(2x + y)(2x - y)] =
  • 2{2x - y)² / [3(2x + y)(2x - y)] =
  • 2(2x - y) / [3(2x + y)]

<u>Simplify the denominator:</u>

  • (4x²y - 2xy²) / (6x + 3y) =
  • 2xy(2x - y) / [3(2x + y)]

<u>Now simplify the remainder of the expression:</u>

  • 2(2x - y) / [3(2x + y)] × [3(2x + y)]/[2xy(2x - y}] =
  • 1/xy
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Step-by-step explanation:

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cestrela7 [59]

Answer:

D: {(-5, -4, 2, 2, 5)}

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Step-by-step explanation:

By definition:

A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a <em><u>relation</u></em> in which no two ordered pairs have the same first component (domain/input/x value) and different second components  (range/output/y value).

Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).

Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.

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