Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So



has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
The bb and j was the source of the questions
Answer:
b. $342
Step-by-step explanation:
Base = Length * width
Base Area = 12 * 5
B = 180 square inches.
Perimeter of the prism will be :
P = 2 (length) + 2 (15)
P = 2 * 12 + 30
P = 54 inches
Height of the jewelry container will be :
X = Ph + 2B
X = 54 * 6 + 2 * 180
X = 684 square inches.
Total cost for paint of jewelry box is :
X * cost per inch
Total cost = 682 * $0.50
Total Cost = $342.
<span>the answer is 59.25 – 8.67 = </span>50.58
Answer:
The solutions are linearly independent because the Wronskian is not equal to 0 for all x.
The value of the Wronskian is 
Step-by-step explanation:
We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

Thus replacing the functions of the exercise we get:

Working with the determinant we get

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.