<h2>
Answer:</h2>
<em><u>Distance of the farmer's rectangular field around the field = 74.46 m</u></em>
<h2>
Step-by-step explanation:</h2>
In the given question,
Length of the rectangular field, L = 20.33 m
Width of the rectangular field, W = 16.9 m
Now,
The area of rectangular field is given by,
The total distance around the rectangular field is,
Distance = Perimeter of the the rectangle.
Perimeter of rectangle = 2(Length + Width)
Perimeter = 2(20.33 + 16.9)
Perimeter = 2(37.23)
Perimeter = 74.46 m
So,
<em><u>Distance of the farmer's rectangular field around the field is = 74.46 m</u></em>
Answer:
The answer is below
Step-by-step explanation:
The equation x² - 3x - 2 cannot be factorized, I think the correct question is:
factorize x² - 3x + 2
Solution:
A quadratic equation is a polynomial equation of the second degree (that is there is at least one term with a degree of 2).
The standard form of a quadratic equation is given by the equation:
ax² + bx + c = 0
Where a, b, and c being constants and x is the unknown variable.
Given:
x² - 3x + 2
= x² - 2x - x + 2
= x(x - 2) -1(x - 2)
= (x - 1)(x - 2)
Since
The square root of 11 is somewhere between 3 and 4. In order to round it to the nearest tenth, we have to try all numbers between 3 and 4 with one decimal digit, and see which is closest to 11 when squared. We have
![\begin{array}{c|c}n&n^2\\3&9\\3.1&9.61\\3.2&10.24\\3.3&10.89\\3.4&11.56\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7Dn%26n%5E2%5C%5C3%269%5C%5C3.1%269.61%5C%5C3.2%2610.24%5C%5C3.3%2610.89%5C%5C3.4%2611.56%5Cend%7Barray%7D%5Cright%5D)
So, the square root of 11 is somewhere between 3.3 and 3.4.
Let x = blank
25 + 5x = 35
5x = 35 - 25
5x = 10
x = 10/5
x = 2
Done!
Solution:
Given:
To get the product of the polynomial; we use the distributive property of multiplication.
Therefore, the product of the polynomials is;
