Vertical angles i believe is the right answer to this problem
Answer:
CODE: 1977.98
Step-by-step explanation:
A.
(To get the closest answer, round the circumference to the nearest ten thousandth.)
C = 2(3.14)r Circumference formula: C = 2πr
C = 2(3.14)(3)
C = 18.84
B.
A = (3.14)r²
A = (3.14)(3)²
A = (3.14)(9)
A ≈ 28.26
C. (It's asking for the circumference.)
C = 2(3.14)r
C = 2(3.14)(58)
C ≈ 364.24
D. (It's a linear pair, which is 180 degrees.)
4x + 2x = 180
6x = 180
x = 30
m∠ABD = 4x
m∠ABD = 4(30)
m∠ABD = 120°
E. (∠GHI & ∠JHK are vertical angles, so they are congruent.)
x + 7 = 3x - 21
28 = 2x
14 = x
F. (x = 14)
m∠JHK = 3x - 21
m∠JHK = 3(14) - 21
m∠JHK = 42 - 21
m∠JHK = 21°
G. (Supplementary - two angles that add up to 180 degrees.)
180 - 84
= 96°
CODE: E(C - D) - F(G - B) - A
CODE: 14(364.24 - 120) - 21(96 - 28.26) - 18.84
CODE: 14(244.24) - 21(67.74) - 18.84
CODE: 3419.36 - 1422.54 - 18.84
CODE: 1977.98
Perpendicular to the line y = 5x - 9
m= -1/5
the line passing through the point (1, 4):
4=-1/5*1+q
q= 21/5
the equation is:
y= -1/5x +21/5
or
x+5y-21=0
Answer:
Length of the person = 1.9 m
Step-by-step explanation:
Actual length of the lorry = 9.5 m
Length of the lorry as per scale = 10 cm
Scale factor used to get the actual length of the lorry = 
= 
= 0.95 : 1
Let the actual length of the person = x meters
Length of the person as per scale = 2 cm
Scale factor used to get the length of person is same.
Therefore, relation between the actual length of the person and scale length will be,

x = 2 × 0.95
x = 1.9 meters