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Whitepunk [10]
3 years ago
8

Can someone solve this question PLEASE?? check the attached pic

Mathematics
1 answer:
Talja [164]3 years ago
5 0

Answer:

someone ur so ugly

Step-by-step explanation:

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One dozen eggs cost $1.98 if the charge is $11.88 how many dozens were purchased
Kazeer [188]

6 dozen were purchased

divide the charge by the cost of one dozen

number purchased = \frac{11.88}{1.98} = 6



3 0
3 years ago
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Can someone help me please ?
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Ask a tutor hope this helps
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If Grace were to invest 1000 at age 25 and not withdrawl any money until retirement at age 67 calculate the expected value of he
alukav5142 [94]

Answer:

9.25% monthly

.095/12 = .0079167

so every month multiply by

1.0079167

y = 1,000 (1.0079167)^(12x)

now just activate your calculator :)

Step-by-step explanation:

4 0
3 years ago
PLEASE HELLLLLLLLLOPP
Scorpion4ik [409]
9/10 * 1000
which would give you 900
6 0
3 years ago
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∫∫(x+y)dxdy ,d là miền giới hạn bởi x²+y²=1
igor_vitrenko [27]

It looks like you want to compute the double integral

\displaystyle \iint_D (x+y) \,\mathrm dx\,\mathrm dy

over the region <em>D</em> with the unit circle <em>x</em> ² + <em>y</em> ² = 1 as its boundary.

Convert to polar coordinates, in which <em>D</em> is given by the set

<em>D</em> = {(<em>r</em>, <em>θ</em>) : 0 ≤ <em>r</em> ≤ 1 and 0 ≤ <em>θ</em> ≤ 2<em>π</em>}

and

<em>x</em> = <em>r</em> cos(<em>θ</em>)

<em>y</em> = <em>r</em> sin(<em>θ</em>)

d<em>x</em> d<em>y</em> = <em>r</em> d<em>r</em> d<em>θ</em>

Then the integral is

\displaystyle \iint_D (x+y)\,\mathrm dx\,\mathrm dy = \iint_D r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \int_0^{2\pi} \int_0^1 r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \underbrace{\left( \int_0^{2\pi}(\cos(\theta)+\sin(\theta))\,\mathrm d\theta \right)}_{\int = 0} \left( \int_0^1 r^2\,\mathrm dr \right) = \boxed{0}

3 0
3 years ago
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