P=2*(L+l)=46
L+l=46:2
L+l=23
(L+l)^2=529
(L^2+l^2)+2l*L=529
D= V L^2+l^2= 17
L^2+l^2=289
so 289+2l*L=529
2l*L=529-289=240
l*L=240:2
A=120
Answer:
The bird will be at a ground distance of 10.04 units away.
Step-by-step explanation:
Vertex of a quadratic function:
Suppose we have a quadratic function in the following format:

It's vertex is the point 
In which


Where

If a<0, the vertex is a maximum point, that is, the maximum value happens at
, and it's value is
.
Equation for the height:
The height of the bird after x seconds is given by:

Which is a quadratic equation with
.
When the bird is at its highest?
Quadratic equation with
, and thus, at the vertex. The ground distance is the x-value of the vertex. Thus

The bird will be at a ground distance of 10.04 units away.
For the given trinomial

We need to multiply a by c

We split the middle term with these two factors

To obtain,

We now factor

This implies
Step-by-step explanation:
c² = a² + b²
c² = 7² + 11²
c² = 49 + 121
c² = 170
now u have to square root it
c² = 170
c = 13