A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 151 feet pe
r second from an initial height of 95 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation:
h = - 16t² + 151t +95
h = - 16t² + 151t +95
1 answer:
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