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Alex
3 years ago
9

A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 151 feet pe

r second from an initial height of 95 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation:
h = - 16t² + 151t +95

Mathematics
1 answer:
madam [21]3 years ago
3 0

Answer:

Step-by-step explanation:

144 = -16t² + 151t + 95

  0 = -16t² + 151t - 49

quadratic formula

t = (-151 ±√(151² - 4(-16)(-49))) / (2(-16))

t = (-151 ± 140.23195) / -32

t = 0.34 s

t = 9.10 s

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