A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 151 feet pe
r second from an initial height of 95 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation:
h = - 16t² + 151t +95
h = - 16t² + 151t +95
1 answer:
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Answer:
The longer diagonal has a length of 7.3 meters.
The angles are 31.65° and 18.35°
Step-by-step explanation:
If one angle of the parallelogram is 50°, another angle is also 50° and the other two angles are the supplement of this angle. so the other three angles are:
50°, 130° and 130°.
The longer diagonal will be the one opposite to the bigger angle (130°), and this diagonal divides the parallelogram in two triangles.
Using the law of cosines in one of these two triangles, we have:
So the longer diagonal has a length of 7.3 meters.
To find the angles that this diagonal forms with the sides, we can use the law of sines:
The other angle is B = 50 - 31.65 = 18.35°
Please check the image attached for better comprehension.
Answer:
Putting the value of x of coordinate point (12,-2)
where x= 12
y= 5×12/6 -12
= 5(2)-12
=10-12 = -2
option D