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Nikolay [14]
3 years ago
7

Kayla has a puppy that weighs 5 pounds. Kayla's brother Manuel has a puppy that is 65 times the weight of Kayla's puppy. Which s

tatement about the weight of Manuel's puppy is true?
Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0
Is there a list of statements? if not i would reason that if
Kayla’s puppy’s weight=k
and we know k=5 (pounds)
and Manuel’s puppy’s weight=m
then your equation would be something like 5*65=m
which means that m=325
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One tank is filling at the rate of 3/4 gallon / 2/3 minute a second tank is filling at the rate of 3/8 gallon per 1/2 minute whi
eduard
\bf \cfrac{\quad \stackrel{gallons}{\frac{3}{4}}\quad }{\stackrel{minutes}{\frac{2}{3}}}\implies \cfrac{3}{4}\cdot \cfrac{3}{2}\implies \cfrac{9}{8}~g/m
\\\\\\
\cfrac{\quad \stackrel{gallons}{\frac{3}{8}}\quad }{\stackrel{minutes}{\frac{1}{2}}}\implies \cfrac{3}{8}\cdot \cfrac{2}{1}\implies \cfrac{3}{4}~g/m\\\\
-------------------------------

\bf \cfrac{3}{4}\cdot \cfrac{2}{2}\implies \cfrac{6}{8}\quad \textit{clearly then }\cfrac{9}{8}\textit{ is larger than }\cfrac{6}{8}
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\stackrel{\stackrel{tank's~volume}{gallons}}{y}=\cfrac{9}{8}\stackrel{minutes}{x}
7 0
3 years ago
Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
Given that €1 =£0.72 a) how much is €410 b) what is the £ to € exchange rate ?
nekit [7.7K]

Answer:

As per the given statement: €1 = £0.72Find how much is €410 in £.then;€410 =  = £295.2Hence, £295.2 much is €410.to find, the exchange rate of £ to €:€1 = £0.72Divide both sides by 0.72 we get;£1 = €1.38

7 0
3 years ago
(-5)2 - 2 x (-9) + 6​
Veronika [31]

Answer:

This is the answer

Step-by-step explanation:

6 0
3 years ago
3.2 Q19<br>Find and interpret f(40)
disa [49]
For (a), f(40) = 0.77(40)^3-878(40)+37764=51,924.

7 0
3 years ago
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