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Keith_Richards [23]
2 years ago
10

El peso que cargan tres pick-ups están en la razón de 2:6:7, cuánto carga el pick-up más grande, si el pick up menor carga 1500k

g?
Mathematics
1 answer:
skad [1K]2 years ago
8 0

Utilizando proporciones, hay que el pick-up más grande carga 5250 kg.

  • Este problema se resuelve por proporciones, por médio de una regla de três.

El peso que cargan tres pick-ups están en la razón de 2:6:7

  • 2 + 6 + 7 = 15.
  • O sea, el pick-up menor carga \frac{2}{15} de el total, que es equivalente a 1500 kg.
  • El pick-up más grande carga \frac{7}{15} de el total, que es equivalente a x kg.

La regla de três es:

\frac{2}{15} - 1500 kg

\frac{7}{15} - x kg

Aplicando multiplicación cruzada:

\frac{2x}{15} = \frac{1500(7)}{15}

2x = 1500(7)

x = \frac{1500(7)}{2}

x = 5250

El pick-up más grande carga 5250 kg.

Un problema similar es dado en brainly.com/question/24615636

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