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rewona [7]
3 years ago
8

Find the vertex: y= -4x^2-8x-7

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0
The vertex occurs a the point (4,-9) 
The easiest way to do this is to draw the graph, or create a table of test values. When you do this, you will see as you increase the value of X, the value of Y continue to shrink until u hit X=4. The graph starts to increase in. So you know that is the vertex. In general, all functions of the form ax^2 +bx + c will have only one vertex. So you can apply this method. 
You might be interested in
Find the area of a rectangle that is 7 cm long and 3 cm wide. You can use the tool to help you solve.
scoundrel [369]

Answer:

21

Step-by-step explanation:

The answer is 21 because for finding the area you have to multiply, 7 and 3.

Multiply 7 and 3 you get 21.

Hope this helps :)

4 0
2 years ago
Read 2 more answers
Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)  

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

            = √(a^2 + b^2 + 40) = 3√10

             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

             a^2 + b^2 = 90 - 40 = 50

            √(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

6 0
3 years ago
In angle abcd if b=50 find the other angles ​
Tom [10]

Answer:

angel abcd is not possible

4 0
3 years ago
Read 2 more answers
Find the error (-8x^2y^2)^2= -64x^4y^4
ExtremeBDS [4]

Answer:

(-8)^2\neq-64

Step-by-step explanation:

Using the distributive property to expand, we have

(-8x^2y^2)^2=(-8)^2(x^2)^2(y^2)^2.

Squaring each term, we have

(-8x^2y^2)^2=64x^4y^4.

The mistake was that 8^2=64, not -64. Using the fact that 8^2=64, the right answer would be

\boxed{64x^4y^4}.

3 0
2 years ago
Read 2 more answers
Solve for x: 22x + 54 = -20 + 60x <br> please help STAT :(
Doss [256]

I think that x = 37/19

22x+54=−20+60x

Step 1: Simplify both sides of the equation.

22x+54=60x−20

Step 2: Subtract 60x from both sides.

22x+54−<u>60x</u>=60x−20−<u>60x</u>

−38x+54=−20

Step 3: Subtract 54 from both sides.

−38x+54−<u>54</u>=−20−<u>54</u>

−38x=−74

Step 4: Divide both sides by -38.

−38x/ <u>−38</u> = −74/<u>−38</u>

x=37/19

8 0
3 years ago
Read 2 more answers
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