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3 years ago

Can someone help me figure this out?

Mathematics

1 answer:

Lyrx [107]3 years ago

3 0

Answer:

Step-by-step explanation:

Let's look at what 10^100 and 100^10 are as numbers without exponents.

Ten raised to a positive integer exponent is a 1 followed by the number of zeros the exponent tells you. For example, 10^2 is 100, or 1 followed by 2 zeros, just like the exponent 2 tells you. 10^5 is 1 followed by 5 zeros, or 100,000. A googol is 10^100 which is a 1 followed by 100 zeros.

Let's use rules of exponents to understand what 100^10 is.

100^10 = (10^2)^10

To raise a power to a power, multiply powers.

100^10 = (10^2)^10 = 10^20

We know what 10^20 means. It is a 1 followed by 20 zeros.

A googol, 10^100, is a 1 followed by 100 zeros.

100^10 is the same as 10^20 or 1 followed by 20 zeros.

A googol is much, much greater than 100^10.

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What is the answer for 1/7(1,000)

12345 [234]

1/7(1000) = 1/7(7000/7)

1*7000
7*7

7000
49

1000
7

so 1/7(1000) = 1000/7 or 142 6/7

5 0

3 years ago

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someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

Area of triangle ABD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

Area of triangle BCD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

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3 years ago

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Anna [14]

Answer:

I believe its a vertical angle

Step-by-step explanation:

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3 years ago

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White raven [17]

To write it in simplest form, you must find a common factor.

In $\frac{3}{9}$ , 3 is a factor of both 3 and 9

3÷3=1 and 9÷3=3

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$\frac{1}{3}$ is your answer in simplest form.

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3 years ago

Write an equation in slope-intercept form for the line that passes through the point (-8, 2) and is perpendicular to the line y

tamaranim1 [39]

Answer:

y = -5x/4 - 8

Step-by-step explanation:

Two lines that are perpendicular have slopes that are opposite reciprocals.

Since the slope of the given line is 4/5, the opposite reciprocal of that is -5/4. So the equation has a slope of -5/4.

Since we know the coordinate of a point of the other equation, we can plug that into the point-slope form equation y - y1 = m(x - x1):

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Simplify:

y - 2 = -5/4(x+8)

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So the equation in slope-intercept form is:

y = -5x/4 - 8

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3 years ago