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3 years ago

Can someone help me figure this out?

Mathematics

1 answer:

Lyrx [107]3 years ago

3 0

Answer:

Step-by-step explanation:

Let's look at what 10^100 and 100^10 are as numbers without exponents.

Ten raised to a positive integer exponent is a 1 followed by the number of zeros the exponent tells you. For example, 10^2 is 100, or 1 followed by 2 zeros, just like the exponent 2 tells you. 10^5 is 1 followed by 5 zeros, or 100,000. A googol is 10^100 which is a 1 followed by 100 zeros.

Let's use rules of exponents to understand what 100^10 is.

100^10 = (10^2)^10

To raise a power to a power, multiply powers.

100^10 = (10^2)^10 = 10^20

We know what 10^20 means. It is a 1 followed by 20 zeros.

A googol, 10^100, is a 1 followed by 100 zeros.

100^10 is the same as 10^20 or 1 followed by 20 zeros.

A googol is much, much greater than 100^10.

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a car reduced its speed in a ratio of 2 to 3 if the final speed was 90 km per hour then what was the original speed.

Licemer1 [7]

Answer:

Orginal Speed is 135

Step-by-step explanation:

The ratio of final speed: original speed is

$\frac{2}{3\\}$

We know that 90 km is it final speed so, we set up a proportion

$\frac{2}{3} =90/x$

$2x=270\\x=135$

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1 year ago

What is the answer for <br> three fourths x equals nine

Dmitry [639]

Answer:

x=12

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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2 years ago

Find each percent increase round to the nearest percent from $5 to $8

asambeis [7]

First subtract the two numbers:

8 - 5 = 3

Now divide this to the original:

3 / 5 = 0.6

Multiply by 100:

0.6 * 100 = 60%

7 0

3 years ago

An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then

Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

$\angle Q=110^\circ$

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

$q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km$

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

$=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)$

(b)Flight Direction of Y

Using Law of Sines

$\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)$

The direction of flight Y to the nearest degree is 39 degrees.

7 0

3 years ago

Eileen collected 78 empty cans to recycle, and Carl collected 62 cans. They packed an equal number of cans into each of seven bo

AVprozaik [17]

Answer:

20 cans

Step-by-step explanation:

Eileen collected 78 empty cans to recycle

Carl collected 62 empty cans to recycle

They pack equal number of cans in 7 boxes

Therefore the number of cans in each boxes can be calculated as follows.

= 62 + 78/7

= 140/7

= 20

Hence there were 20 cans in each boxes

8 0

2 years ago