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DENIUS [597]
3 years ago
14

Pls help !!! 10 pts!!

Mathematics
2 answers:
kiruha [24]3 years ago
5 0

Answer:

16 - 3 = 13 \\ 13 \times(  - 2 )=  - 26

Julios number is 3 or 13

Step-by-step explanation:

hope it help

I'm not sure about julios number

Artist 52 [7]3 years ago
4 0
Julios number is 40 hope this helps
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On Claudia's birthday, her parents open a savings account and deposit SS. They also deposit $50 each
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Wacom down straight to logo and and make sure he don’t get up
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3 years ago
2, 11, 20, 29, 38, 47, 56,...
SIZIF [17.4K]

Answer:

B

Step-by-step explanation:

For example, subtract 56 by 47, you get 9. Each term is 9 more than the previous term.

3 0
3 years ago
3x^2+24x+9=0 in vertex form (completing the square)
Drupady [299]

Answer:

I tried everything and either I'm doing it wrong or you wrote this wrong

Step-by-step explanation:

6 0
3 years ago
A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

Only t=1 belongs to the valid interval 1\leqslant t\leqslant 15

Taking the second derivative

N''(t) = 20(2+\frac{2}{t^2})

Which is always positive, so t=1 is a minimum

(b)

N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

7 0
3 years ago
Evaluate the expression below x/2 +8y-15 for x = -12 and y=3
jeka94
<span>(x/2)+8y-15 = (-12/2)+8*3-15 = -6+24-15 = 33</span>
3 0
3 years ago
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