You know that the other angles must both be acute, as the sum of angles in a triangle is always 180°. since one is more than 100, the other two must add up to less than 80, making both acute.
Answer:
Step-by-step explanation:
If the projectile is hitting something on the ground, it has a height of 0. Sub in a 0 for the h and factor to solve for t:
Factor out a -16t to get
0 = -16t(t - 2.5) which means that either t = 0 or t = 2.5
I'd say it has to be t = 2.5, don't you? ; )
Answer:
<h2>A) 52 units</h2>
Step-by-step explanation:
The formula of a distance between two points X and Y on the number line:
d = |Y - X|
We have
P = -76, Q = -24
Substitute:
d = |-24 - (-76)| = |-24 + 76| = |52| = 52
∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.
... ∠1 = ∠2
... 3x -5 = 2x +15 . . . . substitute the given values
... x = 20 . . . . . . . . . . . add 5-2x
The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.
Answer:
no. 4
Step-by-step explanation:
=25x - 125/x^2 - 25
=25(x-5) / x^2 - 5^2
=25(x-5) / (x-5) (x+5) <use of formula a^2 - b^2=(a-b) (a+b)>
=25/x+5 <cut (x-5) on both side>
