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valentinak56 [21]
2 years ago
14

At Memorial Hospital, 9 of the 12 babies born on Tuesday were boys. In simplest form, what fraction of the babies born on Tuesda

y were boys?
Mathematics
2 answers:
Elza [17]2 years ago
7 0
The answer is 3/4....
QveST [7]2 years ago
6 0
Divide both 9 and 12 by 3. The answer will be 3/4 in simplest form
You might be interested in
If Anna have 8000 and gave jim 300 and bought some items a shoes for 290 a suit for 400 and a phone for 2000
vovangra [49]

Answer: Assuming the unit is dollars, the answer would be $5,010.

Explanation:

Step 1: 8000-300 is 7700.

Step 2: 7700-290 is 7410

Step 3: 7410-400 is 7010

Step 4: 7010-2000 is 5010

So, the answer is Anna has $5,010 dollars left after giving Jim $300, buying shoes for $290, a suit for $400 and spending $2,000 dollars on a new phone.

6 0
3 years ago
A cereal box can hold 144 cubic inches of of cereal. Suppose the box is 8 inches long and
Korvikt [17]

Answer: \\ Volume \:  of \:  the \:  box:V = lwh \\ \Rightarrow h =  \frac{V}{lw}  =  \frac{144}{8 \times 1.5}  =  \frac{144}{12}  = 12 \\ \Rightarrow The  \: box's  \: height:12 \:  inches

5 0
2 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
2 years ago
Peppermint patty is very discourged about her chances on a 10-item true-false quiz. if she randomly answers each question, what
Alexeev081 [22]
Who names their child peppermint patty, I mean the candy is good but you gotta be pretty devoted to it to do that.

6 0
2 years ago
Read 2 more answers
Pls help immediately
STatiana [176]

Answer:

(3,2)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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