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photoshop1234 [79]
3 years ago
8

Donna's TV screen is 20 inches long. If the diagonal measures 25 inches, how long is the width of Donna's TV?

Mathematics
1 answer:
lawyer [7]3 years ago
7 0
25^2 - 20^2 = A^2
225 = A^2
The sq root of 225 = 15
The width of Donna’s TV is 15 inches.
Hope this helps!
I would appreciate it if I got brainliest! Thanks! =D
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Which sentence below represents the number of test questions in the problem below?
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Answer: there are 10 multiple choice questions and 15 short-answer questions

Step-by-step explanation:

Let x represent the number of multiple choice questions in the test.

Let y represent the number of short-answer questions in the test.

If the test has 25 questions, it means that

x + y = 25

Multiple-choice questions are worth 2 points, and short-answer questions are worth 4 points. The test is worth a total of 80 points. It means that

2x + 4y = 80 - - - - - - - -1

Substituting x = 25 - y into equation 1, it becomes

2(25 - y) + 4y = 80

50 - 2y + 4y = 80

- 2y + 4y = 80 - 50

2y = 30

y = 30/2 = 15

x = 25 - y = 25 - 15 = 10

A. The number of multiple-choice questions plus the number of short-answer questions is 25.

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Step-by-step explanation:

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You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard devia
gtnhenbr [62]

Answer:

n=(\frac{2.58(58.2)}{1})^2 =22546.82 \approx 22547

So the answer for this case would be n=22547 rounded up to the nearest integer

Step-by-step explanation:

Let's define some notation

\bar X represent the sample mean

\mu population mean (variable of interest)

\sigma=58.2 represent the population standard deviation

n represent the sample size  

ME =1 represent the margin of error desire

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =+1 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance would be \alpha=0.01 and the critical value z_{\alpha/2}=2.58, replacing into formula (b) we got:

n=(\frac{2.58(58.2)}{1})^2 =22546.82 \approx 22547

So the answer for this case would be n=22547 rounded up to the nearest integer

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