All categories

3 years ago

PLEASE I NEED THE SLOPE OF THE RED LINE AND THE BLUE LIKE BY NOW!!!!

Mathematics

2 answers:

Elodia [21]3 years ago

6 0

Red is 1/3
blue is 2:4

netineya [11]3 years ago

3 0

Red line slope=3/4
Blue line slope=2/3

You might be interested in

I need help I really don’t understand it

FinnZ [79.3K]

Answer:

A B and D

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I need help ASAP please

suter [353]

Answer:

sorry dude I don't know so sorry

8 0

3 years ago

Read 2 more answers

Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

Agata [3.3K]

$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------$

$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o$

8 0

3 years ago

Solve equation 3k+45=8k+25

Brrunno [24]

Answer:

k=4

Step-by-step explanation:

First, we can subtract 3k on both sides. It is ultimately easier to start by subtracting the term with a variable. This would result in 45=5k+25. Then, we can subtract 25 on both sides to get closer to isolating k. This becomes 20=5k. We can then divide by 5 on both sides. This means that k=4.

5 0

3 years ago

Read 2 more answers

Which matrix represents the system of equations shown?

kicyunya [14]

Answer:

by relation

$\binom{3x \: \: - 2y \: \: 12}{4x \: \: \: \: - y \: \: \: \: \: 9} \\ eliminate \: the \: unknowns \: (x \: and \: y) \\ \binom{3 \: \: - 2 \: \: 12}{4 \: \: \: \: - 1 \: \: \: \: \: 9}$

3 0

3 years ago