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3 years ago

Help Please! Find The Area Of A Circle With D=8.2

Mathematics

1 answer:

astraxan [27]3 years ago

8 0

Answer:

52.81

Step-by-step explanat

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What is the constant proportionality of 3 cans and 9 balls

Masja [62]

The constant proportionality is whats left over

3 0

4 years ago

Two similar triangles are shown.

Evgen [1.6K]

Answer:

the answer to this question is 1

8 0

2 years ago

Read 2 more answers

Express your answer in scientific notation. 4.9\cdot 10^{5} - 5.8 \cdot 10^{4} =4.9⋅10 5 −5.8⋅10 4 =4, point, 9, dot, 10, start

tatyana61 [14]

Answer:

$4.32*10^{5}$

Step-by-step explanation:

Given the expression $4.9*10^{5}-5.8*10^{4}$ , to solve the expression, we need to write both scientific notation to the same power of 10.

$5.8*10^{4} is \ expressed\ as \ 0.58*10^{5}$

The expression above becomes $4.9*10^{5}-0.58*10^{5}$ . On taking the difference;

$4.9*10^{5}-0.58*10^{5}\\= (4.9-0.58)*10^{5} \\= 4.32*10^{5}$

The final expression gives the right answer

4 0

3 years ago

Write each trigonometric ratio as a fraction in simplest form. show all supporting work

Nesterboy [21]

Answer: $\frac{x}{20}$

Step-by-step explanation:

Sine uses the ratio, $\frac{opposite}{hypotenuse}$ so we can plug in the information we know. since there is no current value for the opposite side of angle A, we can just use a variable to replace it.

$sinA=\frac{x}{20}$

You can't reduce this any further because there is an unknown variable.

7 0

3 years ago

A clinical trial was conducted to test the effectiveness of a drug for treating insomnia and older subjects before treatment 14

RideAnS [48]

Answer:

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)

Step-by-step explanation:

Step(i):-

Given data mean of the Population = 104 minutes

Given sample size 'n' =14

Mean of the sample(x⁻) = 95.9 minutes

Given Standard deviation = 24.4 minutes

Step(ii):-

99% confidence interval estimate of the mean weight time for a population is determined by

$(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} +Z_{0.01} \frac{S.D}{\sqrt{n} })$

$(95.9 - 2.576\frac{24.4}{\sqrt{14} } , 95.9+2.576\frac{24.4}{\sqrt{14} })$

On calculation , we get

(95.9 -16.79 , 95.9 +16.79)

(79.11 , 112.69)

Conclusion:-

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)

7 0

3 years ago